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3 years ago

True or false an atom is the smallest particle of a whole element

Chemistry

1 answer:

alina1380 [7]3 years ago

5 0

True, as an atom has the same chemical properties as the first bulk element. Dalton’s Atomic Theory explains all :))

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श्रीरयाफल्सन यसका लागि तियरल प्रतिस्थापन स्तर को के हो

jeka94

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3 years ago

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nikdorinn [45]

I think it’s C but not certainly positive

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2 years ago

A sample of xenon occupies a volume of 736 mL at 2.02 atm and 1 °C. If the volume is changed to 416 mL and the temperature is ch

kozerog [31]

Answer:

$\large \boxed{\text{4.63 atm}}$

Explanation:

To solve this problem, we can use the Combined Gas Laws:

$\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}$

Data:

p₁ = 2.02 atm; V₁ = 736 mL; n₁ = n₁; T₁ = 1 °C

p₂ = ?; V₂ = 416 mL; n₂ = n₁; T₂ = 82 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = ( 1 + 273.15) K = 274.15 K

T₂ = (82 + 273.15) K = 355.15 K

(b) Calculate the new pressure

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1} T_{1}} & = & \dfrac{p_{2}V_{2}}{n_{2} T_{2}}\\\\\dfrac{\text{2.02 atm}\times \text{736 mL}}{n _{1}\times \text{274.15 K}} & = &\dfrac{p_{2}\times \text{416 mL}}{n _{1}\times \text{355.15 K}}\\\\\text{5.423 atm} & = &1.171{p_{2}}\\p_{2} & = & \dfrac{\text{5.423 atm}}{1.171}\\\\ & = & \textbf{4.63 atm} \\\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.63 atm}}$}}$

6 0

3 years ago

Which of the following does the internal energy of an ideal gas depend upon?

Serggg [28]

Answer:

The correct option is: a. The internal energy depends upon its temperature.

Explanation:

Ideal gas is a hypothetical gas that obeys the ideal gas law. The equation for the ideal gas law:

P·V=n·R·T

Here, V- volume of gas, P - total pressure of gas, n- total mass or number of moles of gas, T - absolute temperature of gas and R- the gas constant

Also, according to the Joule's second law, the internal energy (U) of the given amount of ideal gas depends on the absolute temperature (T) of the gas only, by the equation:

$U = c_{V}nRT$

Here, $c_{V}$ is the specific heat capacity at constant volume

4 0

3 years ago

What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)

seraphim [82]

Answer:

219.15 grams

Explanation:

What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)

Mole of Na = 22.99g

Mole of Cl = 35.45g

For NaCl we have ratio of 1:1, so we have 1 Na for every Cl

So we just add the two together to get the molar mass of NaCl which is

22.99 + 35.45 = 58.44g/mol

And we know we have 3.75 moles of NaCl so we multiply that by the molar mass of NaCl to get our answer

3.75 x 58.44 = 219.15grams

6 0

3 years ago