Answer:
Yes
Explanation:
The most common energy that is lost in electronic devices is in the form of heat energy.
Answer:
5 m/s 2
To
get the acceleration of a car, you need to know first the difference in the
change in speed of a car then divided by time of the change. This can be
expressed as acceleration =
(change in speed) divided by (time for the change). So 30 m/s minus 10 m/s is
equal to 20 m/s divided by 4 seconds and the quotient is 5 m/s2.
Answer:
the diameter of the nozzle = 3 cm
Explanation:
let the diameter of nozzle be x cm.
then, area of cross-section at nozzle =
nozzle with a speed of 20 m/s, and speed of the water at the faucet is 5 m/s.
area of cross section at faucet = = 9π
now , area×velocity has to be constant (since area×velocity gives volume flow rate which should be same at both ends).
therefore
5×9π = 20×π×x^2/4
=>45 = 5×x^2
=>9 = x^2
=> x = 3 cm (as 3^2 =9)
therefore, the diameter of the nozzle = 3 cm
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Answer:
a)time t = 47.4s
b)speed v = 38.7cm/s
Explanation:
Given:
Total volume of blood = 4.93L × 1000cm^3/L = 4930cm^3
Volumetric rate of flow = 104.1cm^3/s
a) Time taken for all the blood to pass through the aorta is:
Time t = total volume/ volumetric rate
t = 4930/104.1
t = 47.4s
b) Given that the diameter of the aorta is 1.85cm.
V = Av
Where V = Volumetric rate
A = area of aorta
v = speed of blood
v = V/A ...1
Area of a circular aorta = πr^2 = (πd^2)/4
d = 1.85cm
A = (π×1.85^2)/4
A = 2.69cm^2
From equation 1.
v = V/A = 104.1/2.69
v = 38.7 cm/s