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guajiro [1.7K]
4 years ago
9

Why are the plates in a capacitor parallel to each other?

Physics
2 answers:
TiliK225 [7]4 years ago
6 0
To have a uniform field. The field is the voltage between the plates divided by the distance between the plates. If the distance varies so would the field between them.
lukranit [14]4 years ago
6 0

Answer:

to form a uniform electric field between the plates

Explanation:

As we know that the capacitor is a device which is used to store the electrostatic potential energy between the plates.

So here our aim is to design such a capacitor system which will store energy between two plates and that energy will be uniform if the two plates are parallel to each other

If the two plates are not parallel to each other then in that case the field between the plates becomes non uniform and that will form make the charge distribution non uniform.

So here correct answer will be

<em>to form a uniform electric field between the plates </em>

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Please help me with this i dont know it​
Inessa05 [86]

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.

5 0
3 years ago
Describe what long sight is and how it is corrected with a lens
o-na [289]

If long sight means farsighted, then here's your answer:

Farsightedness is when the lens has difficulty focusing on nearby objects. Sufferers must squint to see the nearby objects. Reading, writing, and drawing for longer periods of time can cause eyestrain and headache.

Being farsighted can be corrected with prescription glasses or contact lenses or surgery.

7 0
4 years ago
A reaction has a rate constant of 0.0117 s-1 at 400.0 k and 0.689 s-1 at 450.0 k. calculate the activation energy in kilojoules
Zina [86]
By definition we have to:
 LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
 Where,
 k1 = 0.0117 s-1
 K2 = 0.689 s-1
 T1 = 400.0 k
 T2 = 450.0 k
 R is the ideal gas constant
 R = 8.314 KJ / (Kmol * K)
 Substituting
 ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
 Clearing Ea:
 Ea = 122 kJ
 answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
<span>
</span>
7 0
3 years ago
Read 2 more answers
Two cars are facing each other. Car A is at rest while car B is moving toward car A with a constant velocity of 20 m/s. When car
lapo4ka [179]

Answer:

Let's define t = 0s (the initial time) as the moment when Car A starts moving.

Let's find the movement equations of each car.

A:

We know that Car A accelerations with a constant acceleration of 5m/s^2

Then the acceleration equation is:

A_a(t)  = 5m/s^2

To get the velocity, we integrate over time:

V_a(t) = (5m/s^2)*t + V_0

Where V₀ is the initial velocity of Car A, we know that it starts at rest, so V₀ = 0m/s, the velocity equation is then:

V_a(t) = (5m/s^2)*t

To get the position equation we integrate again over time:

P_a(t) = 0.5*(5m/s^2)*t^2 + P_0

Where P₀ is the initial position of the Car A, we can define P₀ = 0m, then the position equation is:

P_a(t) = 0.5*(5m/s^2)*t^2

Now let's find the equations for car B.

We know that Car B does not accelerate, then it has a constant velocity given by:

V_b(t) =20m/s

To get the position equation, we can integrate:

P_b(t) = (20m/s)*t + P_0

This time P₀ is the initial position of Car B, we know that it starts 100m ahead from car A, then P₀ = 100m, the position equation is:

P_b(t) = (20m/s)*t + 100m

Now we can answer this:

1) The two cars will meet when their position equations are equal, so we must have:

P_a(t) = P_b(t)

We can solve this for t.

0.5*(5m/s^2)*t^2 = (20m/s)*t + 100m\\(2.5 m/s^2)*t^2 - (20m/s)*t - 100m = 0

This is a quadratic equation, the solutions are given by the Bhaskara's formula:

t = \frac{-(-20m/s) \pm \sqrt{(-20m/s)^2 - 4*(2.5m/s^2)*(-100m)}  }{2*2.5m/s^2} = \frac{20m/s \pm 37.42 m/s}{5m/s^2}

We only care for the positive solution, which is:

t = \frac{20m/s + 37.42 m/s}{5m/s^2} = 11.48 s

Car A reaches Car B after 11.48 seconds.

2) How far does car A travel before the two cars meet?

Here we only need to evaluate the position equation for Car A in t = 11.48s:

P_a(11.48s) = 0.5*(5m/s^2)*(11.48s)^2 = 329.48 m

3) What is the velocity of car B when the two cars meet?

Car B is not accelerating, so its velocity does not change, then the velocity of Car B when the two cars meet is 20m/s

4)  What is the velocity of car A when the two cars meet?

Here we need to evaluate the velocity equation for Car A at t = 11.48s

V_a(t) = (5m/s^2)*11.48s = 57.4 m/s

7 0
3 years ago
What are igneous intrusions and extrusions
spayn [35]

Igneous intrusions form when magma cools and solidifies before it can reach the surface. An extrusion consists of extrusive rock; which forms above the surface of the crust.

3 0
3 years ago
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