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3241004551 [841]
2 years ago
8

2. Calculate the [H+] in the following solutions, given their pH, and identify the solution as acidic, basic or neutral.

Chemistry
1 answer:
givi [52]2 years ago
7 0

Answer:

a) acidic; [H+] = 10^-2.5 = 3 x 10^-3

b) basic; [H+] = 10^-11.7 = 2 x 10^-12

c) slightly acidic (almost neutral); [H+] = 10^-6.8 = 1.6 x 10^-7

d) acidic; [H+] = 10^-3.31 = 4.9 x 10^-4

Explanation:

pH < 7 is acidic; pH > 7 is basic; pH = 7 is neutral

[H+] = 10^-pH

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  • This means<u> it is possible to calculate said solubility</u>.

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  • 3.96 g / 36.0 mL = 0.110 g/mL
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In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid
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The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

CV = C_{1}V_{1} + C_{2}V_{2}    (1)      

Where:

C: is the concentration if the mixture = 36%  

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

V = V_{1} + V_{2}

V_{2} = V - V_{1}  (2)

By entering equation (2) into (1), we have:

CV = C_{1}V_{1} + C_{2}(V - V_{1})

36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})

Changing the percent values to decimal ones:

0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})  

Now, by solving the above equation for V₁:

V_{1} = 74.27 mL  

Therefore, the volume of the 39% acid solution is 74.27 mL.

       

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!  

         

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