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fgiga [73]
2 years ago
5

A baby carriage is rolling down a hill at 18 m/s. If the carriage has 90J of kinetic energy, what is the mass of the carriage? a

. 5 kg b. 0.56 kg c. 10 kg d. 100 kg​
Physics
2 answers:
grin007 [14]2 years ago
6 0

Answer:

why did the parents let go of their child-

Explanation:

A 5 kg, because 90 / 18 is 5

vredina [299]2 years ago
5 0

Answer:

cool

Explanation:

You might be interested in
Which of the following is not considered a major work flow structure?
mixas84 [53]

Answer:

The correct option is;

D. Fabrication

Explanation:

A workflow flow is a detailed business process consisting of a series of required interconnected tasks in  directed graph format  that is executable by  workflow management system.

Considering each of the options, we have

A. Work center

This consists of part of the transformation input to output. The location

B. Project

This is the unique identifier of the task to be processed

C. Assembly line

Forms part of the required input where transformation takes place and items are being processed within the assembly line

D. Fabrication

Here the item is fixed, without motion, therefore this is not considered a major work flow structure

E. Continuous flow

Here again, the items are being processed and are in motion, which constitutes a workflow structure.

8 0
2 years ago
Santa doesn't want to push a 25.0 kg wooden box across a wooden floor with a uk of 0.20 at
scZoUnD [109]

Answer:

49 N

Explanation:

In order to move the box at constant speed, the acceleration of the box must be zero (a=0): this means, according to Newton's second law,

F = ma

that the net force acting on the box, F, must be zero as well.

Here there are two forces acting on the box in the horizontal direction while it is moving:

- The force of push applied by the guy, F

- The frictional force, F_f

For an object moving on a flat surface, the frictional force is given by

F_f = \mu_k mg

where

\mu_k is the coefficient of friction

m is the mass of the box

g is the acceleration of gravity

So the equation of the forces becomes

F-\mu_k mg = 0

And substituting:

\mu_k = 0.20\\m = 25.0 kg\\g = 9.8 m/s^2

We find the force that must be applied by the guy:

F=\mu_k mg = (0.20)(25.0)(9.8)=49 N

6 0
2 years ago
Suppose that the acceleration of a model rocket is proportional to the difference between 160 ft/sec and the rocket's velocity.
Levart [38]

Answer:

Explanation:

Given ,

dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

ln ( 160 - v ) = kt + c , where c is a constant

when t = 0 , v = 0

Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = e^{kt}

1 - v / 160 = e^{kt }

v / 160 = 1 - e^{kt }

v = 160 ( 1 - e^{kt } )

differentiating ,

dv / dt = - 160k e^{kt }

acceleration a   = - 160k e^{kt }

given when t = 0 , a = 280

280 = - 160 k

k = - 175

a = - 160 x - 175 e^{kt}

a = 28000 e^{kt}

when a = 128  t = ?

128 = 28000 e^{kt}

e^{kt } = .00457

5 0
2 years ago
Please help 25 points!
cricket20 [7]
<h3>2 Answers:</h3>

a) Velocity is a vector quantity

e) Velocity is a speed with direction

=================================================

Explanation:

If we know the velocity of an object, then we know how fast it's going (speed) and where it's going (direction). It is a vector because the direction of the vector determines the direction, and the length of the vector (aka magnitude) determines the speed. So in a sense we've built in two facts of data into one visual.

An example of velocity: 10 miles per hour north. Here we have the speed of 10 mph and the direction north.

-------------------

Extra info:

  • Choice B contradicts choice A, so we can cross choice B off the list.
  • Choice C is false because speed is a scalar, or single quantity, and not a vector. As mentioned earlier, speed is a part of velocity, but they aren't the same exact thing.
  • Choice D is false because the velocity does not account for net force. We don't have any force information built into the velocity.
8 0
3 years ago
Read 2 more answers
If a car accelerates from a speed of 10 m/s at an acceleration of 2 m/s2 for 3s.
Flauer [41]

Answer:

\boxed{\sf Final \ speed \ of \ the \ car = 16 \ m/s}

Given:

Initial speed (u) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken (t) = 3s

To Find:

Final speed (v) of the car

Explanation:

From equation of motion we have:

\boxed{ \bold{v = u + at}}

By substituting value of u, a & t in the equation we get:

\sf \implies v = 10  + 2\times 3 \\  \\ \sf \implies v = 10 + 6 \\  \\ \sf \implies v = 16 \: m {s}^{ - 1}

\therefore

Final speed (v) of the car = 16 m/s

3 0
3 years ago
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