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ehidna [41]
3 years ago
6

Sodium forms a 1+ ion, while fluorine forms a 1-lon. Write the electron configuration for each ion. Why don't these two elements

form 2+ and
2-ions, respectively?
​
Chemistry
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer:

Explanation:

Given elements:

    Sodium

    Fluorine

The ion Na⁺ is made up of 10 electrons, its electronic configuration is:

            1s² 2s² 2p⁶

Ion F⁻ is made up of 10 electrons, its electronic configuration is:

           1s² 2s² 2p⁶

These ions do not form +2 because they cannot attain stability by losing or gaining two electrons.

Sodium atom is made up of one valence electron. If it loses one electron, it will be isoelectronic with Neon.

Fluorine has 7 valence electrons, to attain stability, it must gain one electron to form an octet. This way it will be isoelectronic with Neon.

Losing or gaining two electrons will not make the elements attain stability.

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An unknown noble gas has a density of 5.84 g dm-3 at STP. Calculate its molar mass, and so identify the gas.
bagirrra123 [75]

The noble gas is Xenon and its molar mass is 131 g/mol.

<h3>What is the molar mass of the noble gas?</h3>

The molar mass of the noble gas is determined as follows;

Let molar mass of unknown gas be M, and mass of gas be m

Density of the noble gas, ρ = 5.8 g/dm³

density = m/V

At STP;

  • temperature, T = 273.15 K
  • pressure, P = 1 atm
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From ideal gas equation:

PV = nRT

where n = m/M

PV = mRT/M

M = mRT/PV

M =  0.0821 * 273.15 * 5.84/1

Molar mass of the noble gas = 131 g/mol

The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.

Learn more about molar mass at: brainly.com/question/837939

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6 0
1 year ago
Write formula of compound given two chemicals
Evgesh-ka [11]
Nitrous oxide has 2 nitrogen atoms and 1 oxygen atom per molecule
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3 years ago
The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

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4 years ago
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