Changes. the dependent variable is affected by the independent variable
KCIO3 → KCI + O2
First you have to count all the atoms of each element in both sides of the reaction, in this case:
Left side: there is one K atom, one Cl atom and 3 O atoms
Right side: there is one K atom, one Cl atom and 2 O atoms
K and Cl are balanced but O isn't
To balance O you can add a coefficient to O2 in the right side of the equation like this:
KCIO3 → KCI +3 O2
Now you have 6 oxygen atoms in the right side but only 3 in the left side, so you can add a coefficient to KClO3:
2KCIO3 → KCI +3 O2
And finally, Balance K and Cl again by adding a 2 as a coefficient for KCl
2KCIO3 → 2KCI +3 O2
Now both sides have the same amount of atoms of each element (2 K atoms, 2 Cl atoms and 6 O atoms)
Answer:
1. Both
2. Phosphorylation
3. Both
4. Phosphorylation
5. Oxidative.
6. Both
Explanation:
Phosphorylation only occurs in chloroplast and it involves larger electrical component. Both Phosphorylation and oxidative occurs in mitochondria and it involves proton gradient. They occur in plants to produce ATP. Oxidative involves in smaller electrical component.
In the given system, A is the central atom which is surrounded by four B atoms and forms 4 covalent bonds. Ideally, this structure could correspond to a square planar molecular geometry. However, there are two lone pairs of electrons on the central atom A which must be considered in order interpret the electron geometry.
Thus the electron domain geometry around A is octahedral
