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Nastasia [14]
3 years ago
11

6) There are two reactants in a chemical equation, and one product. The mass of the product is 40g. The mass of the first reacta

nt is 16g. What must the mass of the second reactant be, if the equation is to follow the law of conservation of mass?​
Physics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

24g

Explanation:

mass of the product is 40g.

The mass of the first reactant is 16g

The mass of the second reactant  = ?

  Let the first reactant  = A

   Let the second reactant  = B

  Let the product  = C

Equation of reaction;

           A   +  B    →  C

           16g              40g

The mass of B must be  = 40 -16  = 24g

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8 0
4 years ago
In a lab, four balls have the same velocities but different masses.
olya-2409 [2.1K]

Answer:

New Momentum of Ball B=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}

<u>Explanation:</u>

Given:

Mass of Ball A=1kg

Mass of Ball B= 2kg

Mass of Ball C=5kg

Mass of Ball D=7kg

Velocities of A=B=C=D=2.2\frac{m}{s}

Momentum of Ball A=2.2\frac{k g m}{s}

Momentum of Ball B=4.4 \frac{k g m}{s}

Momentum of Ball C=11\frac{k g m}{s}

Momentum of Ball D=15\frac{k g m}{s}

To Find:

Change in Momentum When of Ball B gets tripled

Solution:

Though all balls have same velocity, thus we get

Velocities of A=B=C=D=2.2\frac{m}{s}

Initial Momentum of Ball B=4.4\frac{k g m}{s}

If the Mass of Ball B gets tripled;

We get New Mass of Ball B=3×Actual Mass of the ball

                                            =3×2=6kg

Thus we get Mass of Ball B=6kg

According to the formula,  

Change in momentum of Ball B \Delta p=m \times \Delta v

Where \Delta p=change in momentum

          m=mass of the ball B

         \Delta v=change in velocity ball B

And \Delta v=v, since all balls, have same velocity

Thus the above equation, changes to

         \Delta p=m \times v

Substitute all the values in the above equation we get

         \Delta p=6 \times 2.2

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Result:

 Thus the New Momentum of ball B=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}

3 0
3 years ago
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Answer:

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What is the separation in meters between two slits for which 617 nm orange light has its first maximum at an angle of 29. 8°?
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The separation between the two slits, d is related to the wavelength, and angle using the formula below. Hence, the value of d is 1.22 x 10⁻⁶ m.

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The double-slit experiment is a demonstration that light and matter can display characteristics of both classically defined waves and particles; moreover, it displays the fundamentally probabilistic nature of quantum mechanical phenomena.

This type of experiment was first performed, using light, by Thomas Young in 1802, as a demonstration of the wave behavior of light. At that time it was thought that light consisted of either waves or particles.

With the beginning of modern physics, about a hundred years later, it was realized that light could in fact show behavior characteristic of both waves and particles. Young's experiment with light was part of classical physics long before the development of quantum mechanics and the concept of wave–particle duality.

Learn more about double-slit experiment here : brainly.com/question/24196355

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