Answer:
.
Explanation:
Eardrum or tympanic membrane changes sound to vibration and pass through malleus, incus and stapes.
Maybe it’s c ??? I’m not too sure sorry
Answer:
![\boxed {\boxed {\sf B. \ 22 \ grams}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20B.%20%5C%2022%20%5C%20grams%7D%7D)
Explanation:
We need to use the formula for heat of vaporization.
![Q=H_{vap}*m](https://tex.z-dn.net/?f=Q%3DH_%7Bvap%7D%2Am)
Identify the variables.
- The heat absorbed by the evaporating water is the <u>latent heat of vaporization. </u>For water, that is 2260 Joules per gram.
- Q is the energy, in this problem, 50,000 Joules.
- m is the mass, which is unknown.
![H_{vap}=2260 \ J/g\\Q=50,000 \ J \\](https://tex.z-dn.net/?f=H_%7Bvap%7D%3D2260%20%5C%20J%2Fg%5C%5CQ%3D50%2C000%20%5C%20J%20%5C%5C)
Substitute the values into the formula.
![50,000 \ J=2260 \ J/g*m](https://tex.z-dn.net/?f=50%2C000%20%5C%20J%3D2260%20%5C%20J%2Fg%2Am)
We want to find the mass. We must isolate the variable, m.
m is being multiplied by 2260 J/g. The inverse operation of multiplication is division. Divide both sides by 2260 J/g.
![\frac{50,000 \ J}{2260 \ J/g} =\frac{2260 \ J/g*m}{2260 \ J/g}](https://tex.z-dn.net/?f=%5Cfrac%7B50%2C000%20%5C%20J%7D%7B2260%20%5C%20J%2Fg%7D%20%3D%5Cfrac%7B2260%20%5C%20J%2Fg%2Am%7D%7B2260%20%5C%20J%2Fg%7D)
![\frac{50,000 \ J}{2260 \ J/g} =m](https://tex.z-dn.net/?f=%5Cfrac%7B50%2C000%20%5C%20J%7D%7B2260%20%5C%20J%2Fg%7D%20%3Dm)
Divide. Note that the Joules (J) will cancel each other out.
![\frac{50,000 \ }{2260 \ g} =m](https://tex.z-dn.net/?f=%5Cfrac%7B50%2C000%20%5C%20%7D%7B2260%20%5C%20g%7D%20%3Dm)
![22.1238938 \ g =m](https://tex.z-dn.net/?f=22.1238938%20%5C%20g%20%3Dm)
Round to the nearest whole number. The 1 in the tenth place tells us to leave the number as is.
![22 \ g \approx m](https://tex.z-dn.net/?f=22%20%5C%20g%20%5Capprox%20m)
The mass is about 22 grams, so choice B is correct.
Answer:
salt water, soda, orange juice, coffee
Explanation:
From ideal gas law that is p=nRT/V
n is the total moles
moles of co2=2.34/44=0.053
SO2=1.73/64=0.027
Ar=3.33/40=0.083
total moles=0.053+0.027+0.083=0.163moles
therefore p=[0.163mole x 62.364 torr/mole/k x(42 +273.15k)] /12.2 l=262.6 torr