Briana pushed a 5 kg box of dance flyers with a force of 10 N. What is the acceleration of the box?

For a ship moving against the current, it takes 9 hours to cover a distance of 113.4 miles. how much does it take this ship to r

Digiron [165]

Let x mph be the speed of the ship in still water.
Against the current, the net speed is, (x-1.9) mph.
Time, t= distance, d/ Speed, v => 9= 113.4/(x-1.9) => 9(x-1.9) = 113.4 => x-1.9 = 113.4/9 => x = 12.6+1.9 = 14.5 mph

Moving with the current, the net speed of the ship = 14.5+1.9 =16.4 mph

Time take, t = d/v = 113.4/16.4 = 6.915 hours

3 0

3 years ago

Read 2 more answers

A wooden block of mass 2kg is 20cm thick ,10cm wide and 30cm tall

Kitty [74]

Answer:

A.33333.3N/M2

B.100000N/M2

Explanation:

HAVE A NICE DAY ;]

The formula is $\frac{Newton}{Meter^{2} }$

10 Newton=1 kilogram

6 0

3 years ago

Read 2 more answers

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston tha

Makovka662 [10]

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

<h3>What is pascal law?</h3>

Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.

Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\$

In case of radius,

$\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}$

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,

$r_1=2.67\rm\; cm$

$r_2=20.0\rm\; cm$

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,

$F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N$

Put the values in the above formula,

$\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N$

Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

Learn more about the pascal law here;

brainly.com/question/4262025

#SPJ4

4 0

2 years ago

The part of the electromagnetic spectrum usually used for communication is

noname [10]

<h2>Answer:</h2>

The part of the electromagnetic spectrum usually used for communication is of radio waves, infrared waves and microwaves.

But most common waves used in communication are radio waves.

<h3>Explanation:</h3>

Radio waves are used to transmit television and radio programmes.
While microwaves are used for mobile phones and Wi-Fi.
Radio waves are a type of electromagnetic radiation with wavelengths in the electromagnetic spectrum longer than infrared light.
Radio waves have frequencies as high as 300 gigahertz (GHz) to as low as 30 hertz (Hz).

5 0

3 years ago

In a double-slit experiment, it is observed that the distance between adjacent maxima on a remote screen is 1.0 cm. What happens

kobusy [5.1K]

Answer:

C) It increases to 2.0 cm

Explanation:

In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by

$\Delta y = \frac{\lambda D}{d}$

where

$\lambda$ is the wavelength of the wave

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is

$d'=\frac{d}{2}$

Substituting into the equation, we find that the new separation between the maxima is

$\Delta y' = \frac{\lambda D}{d/2}=2(\frac{\lambda D}{d})=2\Delta y$

So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.

5 0

3 years ago