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sesenic [268]
3 years ago
13

The man rolls the cupboard at a steady speed from the lorry to the house. The friction force in the wheels is 40 N. State the fo

rce with which the man has to push.
Physics
1 answer:
tamaranim1 [39]3 years ago
4 0

Answer:

40N

Explanation:

Using the newton's second law of motion

\sum Fx = max

Fm - Ff = max

Fm is the applied force

Ff is the frictional force

m is the mas of the cupboard

ax is the acceleration

Since the speed from the lorry is steady, ax = 0m/s^2

Also Ff = 40N

Substitute into  the formula;

Fm - 40 = m(0)

Fm - 40 = 0

Add 40 to both sides

Fm - 40 + 40 = 0 + 40

Fm = 40N

Hence the force with which the man applied to push is 40N

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Distance between the two cars is increasing at the rate of 85 mph. 

A passenger in Car-1 says that he is at rest in his own frame of reference,
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An egg is thrown upward with a velocity of 4.5 m/s. How long will it take to reach it's maximum height?
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Answer:

0.45 seconds

Explanation:

Letting the value of g = 10 m/s/s

final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)

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acceleration = -10 m/s/s (since the gravity is acting against the egg)

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<em>v = u + at</em>

<em>0 = 4.5 + (-10)t</em>

<em>t = -4.5 / -10</em>

t = 0.45 seconds

3 0
3 years ago
A certain white dwarf star was once an average star like our Sun. But now it is in the last stage of its evolution and is the si
solmaris [256]

Answer:

4.384 * 10^13

Explanation:

Given the expression :

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Applying the laws of indices

[(6.67 * 1.99) *10^(-11 + 30)] ÷ [(1.74 * 1.74) * 10^3+3]

13.2733 * 10^19 ÷ 3.0276 * 10^6

(13.2733 / 3.0276) * 10^(19 - 6)

4.3840996 * 10^13

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Which type of radiation travels at the speed of light and penetrates matter easily?
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3 years ago
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Light bulb 1 operates with a filament temperature of 2700 K whereas light bulb 2 has a filament temperature of 2100 K. Both fila
Lemur [1.5K]

Answer:

0.3659

Explanation:

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A =Area

e = transmittivity

σ = Stefan-boltzmann constant

T = Temperature

since both the bulbs radiate same power

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2 denotes the bulb 2

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A₁e₁σT₁⁴ = A₂e₂σT₂⁴

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