Can't you look it up or something? Idk what it is but I can try and look it up for ya! If you want
Answer:
h = 16.9 m
Explanation:
When a ball is thrown upward, its velocity gradually decreases, until it stops for a moment, when it reaches the maximum height, while its height increases. Thus, the law conservation of energy states in this case, that:
Kinetic Energy Lost by Ball = Potential Energy Gained by Ball
(0.5)m(Vf² - Vi²) = mgh
h = (0.5)(Vf² - Vi²)/g
where,
Vf = Final Speed of Ball = 0 m/s (Since, ball stops for a moment at highest point)
Vi = Initial Speed of Ball = 18.2 m/s
g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)
h = maximum height the ball can reach = ?
Therefore, using values in the equation, we get:
h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)
<u>h = 16.9 m</u>
Answer:
correct answer is narrow
Explanation:
solution
when we pass someone riding bicycle ahead you then we should decrease our speed and increase the distance between you and bicyclist
and we should ride on road with very predictable manner and we should ride in straight line and if If road is too narrow for a bicycle
then we should ride vehicle to travel side by side so bicyclist should occupy lane until it safe
so here correct option is narrow
Explanation:
For this problem we have to take into account the expression
J = I/area = I/(π*r^(2))
By taking I we have
I = π*r^(2)*J
(a)
For Ja = J0r/R the current is not constant in the wire. Hence
and on the surface the current is
(b)
For Jb = J0(1 - r/R)
and on the surface
(c)
Ja maximizes the current density near the wire's surface
Additional point
The total current in the wire is obtained by integrating
and in a simmilar way for Jb
![I_{T}=\pi J_{0} \int\limits^R_0 {r^{2}(1-r/R)} \, dr = \pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2R}]=\pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2}]](https://tex.z-dn.net/?f=I_%7BT%7D%3D%5Cpi%20J_%7B0%7D%20%5Cint%5Climits%5ER_0%20%7Br%5E%7B2%7D%281-r%2FR%29%7D%20%5C%2C%20dr%20%3D%20%5Cpi%20%20%20J_%7B0%7D%5B%5Cfrac%7BR%5E%7B3%7D%7D%7B3%7D-%5Cfrac%7BR%5E%7B2%7D%7D%7B2R%7D%5D%3D%5Cpi%20J_%7B0%7D%5B%5Cfrac%7BR%5E%7B3%7D%7D%7B3%7D-%5Cfrac%7BR%5E%7B2%7D%7D%7B2%7D%5D)
And it is only necessary to replace J0 and R.
I hope this is useful for you
regards
