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2 years ago

I WANT TO PLAY UNDERTALE PLS HELP 100 PTS SINENCE

Physics

2 answers:

Artyom0805 [142]2 years ago

8 0

Answer:

Go to Undertale.com and buy it

Explanation:

sorry i don't really know how to answer this

spin [16.1K]2 years ago

6 0

Answer:

Use IGG Games or get money.

Explanation:

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Air is a good medium for sound waves because it is

Paul [167]

Answer:

air does not have a modulus of rigidity.

Explanation:

Since air is completely elastic medium, that is, it does not have a modulus of rigidity, therefore sound waves in air are longitudinal.

4 0

1 year ago

Recall that if a line is parallel to the vector v and passes through the point P0, which is the tip of the position vector r0, t

Elenna [48]

Answer:

The vector equation of the line is

$\overrightarrow{r}=+t$

Parametric equations for given line are

$x=7+t\\y=-8+6t\\z=3-13t$

Explanation:

The vector equation of the line is given by

$r(t) = r_{o} + tv$

r₀ = (7, -8, 3)

v = (1, 6, -13)

At these points the vector equation for this line is:

$\overrightarrow{r}=\overrightarrow{r_{o}}+t\overrightarrow{v}\\\overrightarrow{r}=+t$

Parametric equations for given line are

$x=7+t\\y=-8+6t\\z=3-13t$

8 0

2 years ago

1. A kangaroo hops 84 m to the east in 7 seconds.

DENIUS [597]

Explanation:

Given parameters:

Distance hopped = 84m

Displacement = 84m due east

Time = 7s

Unknown:

Speed of kangaroo = ?

Velocity of kangaroo = ?

Solution:

To solve this problem,

Speed = $\frac{distance}{time }$ = $\frac{84}{7}$ = 12m/s

Velocity = $\frac{displacement}{time}$ = $\frac{84}{7}$ = 12m/s due east

3 0

2 years ago

Three students have been studying relative motion and decide to do an experiment to demonstrate their knowledge. The experiment

miskamm [114]

Answer with Explanation:

We are given that

Constant speed of Jane=12.6 m/s

a.When Fred can throw the ball 30 m/s

We have to find the angle relative to the horizontal when he throw the ball in order for Sue to see the ball travel vertically upward.

Let $\theta$ be the angle .

Therefore,

$30 cos\theta=12.6$

$cos\theta=\frac{12.6}{30}=0.42$

$\theta=cos^{-1}(0.42)=65.165^{\circ}$

b.We have to find the height to which ball reach.

$v^2-v^2_0=2aS$

$S=\frac{v^2-v^2_0}{2a}=\frac{0-(30 sin65.165)^2}{2(-9.81)}$

$S=37.78 m$

7 0

3 years ago

Can you please give me the answers ?

rodikova [14]

Answer:

237

Explanation:

7 0

2 years ago