Determine the total pressure of a mixture of 0.400 mole of He and 0.600 mole of Ne in a 2.00 liter container at 25oC.
1 answer:
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Answer:
The concentration of cyclopropane after 22.0 hour is 0.0457 M.
Explanation:
Conversion of cyclopropane into propene follows first order kinetics.
The integrated rate of first order kinetic is given by :
= Initial concentration of reactant
= final concentration of reactant after time t
k = rate constant of the reaction
We have :
Rate constant of the reaction = k =
t = 22.0 hour
[A] =?
The concentration of cyclopropane after 22.0 hour is 0.0457 M.
Answer:
17.3 g
Explanation:
<u>Given the following data;</u>
- Quantity of heat, Q = 0.507 J
- Temperature = 0.007°C
- Specific heat capacity of water = 4.2 J/g°C
Mathematically, Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- M represents the mass of an object.
- C represents the specific heat capacity of water.
- T represents the temperature.
Making "M" the subject of formula, we have;
Substituting the values into the formula, we have;
<em>Mass, m = 17.3 grams</em>