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LekaFEV [45]
3 years ago
11

Determine the total pressure of a mixture of 0.400 mole of He and 0.600 mole of Ne in a 2.00 liter container at 25oC.

Chemistry
1 answer:
harina [27]3 years ago
8 0

Answer:

Total pressure of the mixture is 12.2 atm

Explanation:

Let's apply the Ideal Gases law to solve this

Total pressure . V = Total moles . R . T

Total moles = 0.4 m of He and 0.6 mole of Ne → 1 mol

P . 2L = 1 mol . 0.082 L.atm/mol. K . 298K

P = ( 1 mol . 0.082 L.atm/mol. K . 298K) /2L

P = 12.2 atm

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PLEASE I REALLY NEED ANSWER REAL QUICK
DENIUS [597]

Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

    5% of 800  =  \frac{5}{100} × 800

                       = 5 × 8

                       = 40 g

The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

                               = 800 - 40

                              = 760 g

Therefore, the mass of water required is 760 g.

5 0
4 years ago
How many valence electrons are represented in the following electron configuration? 1s22s22p5
Alex
Answer is: d) 7.
Electron configuration: 1s²2s²2p⁵.
<span>Valence electrons are in 2s and 2p orbitals.
</span>Valence electrons<span> are outer shell </span>electrons (transition metal can have a valence electrons in an inner shell) <span>that is associated with an </span>atom <span>and they can form </span>chemical bond. V<span>alence eletrons determine chemical proporties of element.</span>
7 0
3 years ago
How do unbalanced forces affect its motion when the object is at rest?
Eddi Din [679]
<span>An unbalanced force acting on a body at rest will change the motion of the body. The of motion is measured by its momentum.</span>
4 0
3 years ago
a compound has a percent compostion of carbon equal to 48.8383%, hydrogen equal to 8.1636%, and oxygen equal to 43.1981%. what i
Margarita [4]

Answer:

C₂H₃O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 48.8383%

Hydrogen (H) = 8.1636%

Oxygen (O) = 43.1981%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 48.8383%

H = 8.1636%

O = 43.1981%

Divide by their molar mass

C = 48.8383 / 12 = 4.07

H = 8.1636 / 1 = 8.1636

O = 43.1981 / 16 = 2.7

Divide by the smallest

C = 4.07 / 2.7 = 2

H = 8.1636 / 2.7 = 3

O = 2.7 /2.7 = 1

Thus, the empirical formula of the compound is C₂H₃O

8 0
3 years ago
Describe what is happening to the density of the aqueos solution as salt is being added​
Gala2k [10]
Key concepts
Density
Mass
Volume
Concentration
Buoyancy
Water
3 0
3 years ago
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