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Butoxors [25]
3 years ago
7

What happened to the pod during those seconds when communication was lost?

Physics
2 answers:
Paraphin [41]3 years ago
6 0

Answer:

it blew up

Explanation:

i don't know

iragen [17]3 years ago
4 0

Answer:

Explanation:

From our investigation of what forces are like in a collision, we learned that when two

objects collide, a force is exerted on each object. The two forces are in opposite

directions but the same strength. This allowed us to infer that an equal strength force

was exerted on the space station and the pod, but in opposite directions.

As a result, the space station and the pod are moving in opposite directions. We need to

learn more about the effects of collisions on each object’s motion so we can report back

to Dr. Gonzales at the space agency.

You will use physical materials to gather data about

forces in a collision. You will also notice how objects

are affected by collisions. Students will use their

data to infer the force direction for objects in a

collision.

Based on the velocity change of each object,

what did you infer about the direction of forces

during a collision?

• We observed that the velocity of each object changed during a collision, so we can infer

that a force had to be exerted on each object. However, the motion of the objects

changed in different ways.

• The object that was moving forward slowed down, so I can infer that the force must have

pushed backward on this object.

• The other object started moving forward, so the force must have pushed forward on that

object. If one force was backward and one force was forward, then the forces pushed

the objects in opposite directions.

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You are heading toward an island in your speed boat when you see a friend standing on the shore of the island. You sound the boa
monitta

Answer:

Greater than

Explanation:

The Wavelength will be higher than what will be heard without any motion on the boat due to the Doppler Effect, which is the change in the frequency of a sound wave whenever there's a relative motion between the source of the wave and observer. The amount of shift in frequency depends on the speed of the source towards the observer; the higher the velocity of the source, the higher the shift.

8 0
3 years ago
Which of the following is an example of Newton's second law of motion?
laiz [17]

Answer:

B

Explanation:

Newton’s Second Law of Motion

Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.

This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.

The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.

5 0
3 years ago
Read 2 more answers
Https://phet.colorado.edu/sims/html/balloons-and-static-electricity/latest/balloons-and-static-electricity_en.html
Katarina [22]

Answer:

there is not pic

Explanation:

5 0
2 years ago
A-10A twin-jet close-support airplane is approximately rectangular with a wingspan (the length perpendicular to the flow directi
Sidana [21]

Solution :

Given :

Rectangular wingspan

Length,L = 17.5 m

Chord, c = 3 m

Free stream velocity of flow, $V_{\infty}$ = 200 m/s

Given that the flow is laminar.

$Re_L=\frac{\rho V L}{\mu _{\infty}}$

      $=\frac{1.225 \times 200 \times 3}{1.789 \times 10^{-5}}$

    $= 4.10 \times 10^7$

So boundary layer thickness,

$\delta_{L} = \frac{5.2 L}{\sqrt{Re_L}}$

$\delta_{L} = \frac{5.2 \times 3}{\sqrt{4.1 \times 10^7}}$

    = 0.0024 m

The dynamic pressure, $q_{\infty} =\frac{1}{2} \rho V^2_{\infty}$

                                           $ =\frac{1}{2} \times 1.225  \times 200^2$

                                          $=2.45 \times 10^4 \ N/m^2$

The skin friction drag co-efficient is given by

$C_f = \frac{1.328}{\sqrt{Re_L}}$

     $=\frac{1.328}{\sqrt{4.1 \times 10^7}}$

     = 0.00021

$D_{skinfriction} = \frac{1}{2} \rho V^2_{\infty}S C_f$

                  $=\frac{1}{2} \times 1.225 \times 200^2 \times 17.5 \times 3 \times 0.00021$

                  = 270 N

Therefore the net drag = 270 x 2

                                      = 540 N

7 0
2 years ago
A rocket of mass 40000kg propelled by a force of 10^6N acquires a speed of 3000m/s determine the power expended
Katyanochek1 [597]

Answer:

3×10⁹ W

Explanation:

Power = work / time

Power = force × distance / time

Power = force × velocity

P = Fv

P = (10⁶ N) (3000 m/s)

P = 3×10⁹ W

6 0
3 years ago
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