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KIM [24]
3 years ago
13

The heating curve shows the energy gain of a substance as it changes from solid to gas. Which section of the graph shows the liq

uid phase of
the substance gaining kinetic energy?

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
3 0

Answer:

phase c show the liquid bas it is less from 100 and more from 0

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How many moles of sulfur<br> dioxide are in 2.26 x 10^33 sulfur dioxide molecules?
LUCKY_DIMON [66]

Answer:

moles = no. of molecules / Avogadro's number

         = 2.26 x 10^33 / 6.022 x 10^23

         = 3752906011

Round to significant figures which is 3 = 3.75 x 10^9 mol

Explanation: The formula for finding how many moles of a substance when given the amount of molecules is: moles = number of molecules / Avogadro's number

6 0
3 years ago
Convert each quantity to the indicated units. a. 3.01g to cg. b. 6200m to km
miss Akunina [59]

a. 301 cg

b. 6.2 km

Explanation:

a. knowing that 1 gram (g) is equal to 100 centigrams (cg) we devise the following reasoning:

if        1 g is equal to 100 cg

then  3.01 g are equal to X cg

X = (3.01 × 100) / 1 = 301 cg

b. knowing that 1 kilometer (km) is equal to 1000 meters (m) we devise the following reasoning:

if         1 km is equal to 1000 m

then   Y km are equal to 6200 m

Y = (6200 × 1) / 1000 = 6.2 km

Learn more about:

converting units of measurement

brainly.com/question/11300981

#learnwithBrainly

5 0
3 years ago
Which of the following is a small-scale, sudden natural change?
stellarik [79]
D because yes it works very slow 
7 0
3 years ago
Is copper ii sulphate (solution) blue or green?
slavikrds [6]
Copper II sulfate solution is blue.
8 0
3 years ago
Carbon dioxide in the atmosphere dissolves in raindrops to produce carbonic acid (H2CO3), causing the pH of clean, unpolluted ra
anastassius [24]

Answer:

The range of [H⁺] is from 2.51 x 10⁻⁶ M to 6.31 x 10⁻⁶ M,

Explanation:

To answer this problem we need to keep in mind the <u>definition of pH</u>:

  • pH = -log [H⁺]

So now we <u>calculate [H⁺] using a pH value of 5.2 and of 5.6</u>:

  • 5.2 = -log [H⁺]

-5.2 = log [H⁺]

10^{-5.2} = [H⁺]

6.31 x 10⁻⁶ M = [H⁺]

  • 5.6 = -log [H⁺]

-5.6 = log [H⁺]

10^{-5.6} = [H⁺]

2.51 x 10⁻⁶ M = [H⁺]

6 0
3 years ago
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