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Mrrafil [7]
3 years ago
5

An increase in aurora activity on Earth could be related to what activity on the Sun?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

D.

Explanation:

INCREASE OF SOLAR WINDS When the sun is more active

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H2(g)+p4(s)ph3(g) what the answer ?
disa [49]

Answer:

6H2 + P4→ 4PH3

Explanation:

Phosphorus has 4 in it and hydrogen has 3 in it. in order to balance it, we have to put 4 in front of phosphine so that the phosphorus on the product side has an equal amount as to the one on the reactant side.

the only one left to balance is hydrogen and so in order to balance it we put a 6 on h2 because the hydrogen in the product size becomes 12 (4 * 3).

therefore the hydrogen on the reactant side becomes 12 as well (6 * 2)

8 0
3 years ago
Use the definition of molarity to calculate the concentration of 12.34 g of CaSO4 completely dissolved in water, with a solution
Ede4ka [16]

Answer:

[CaSO₄] = 36.26×10⁻² mol/L

Explanation:

Molarity (M) → mol/L → moles of solute in 1L of solution

Let's convert the volume from mL to L

250 mL . 1L/1000 mL = 0.250L

We need to determine the moles of solute. (mass / molar mass)

12.34 g / 136.13 g/mol = 0.0906 mol

M → 0.0906 mol / 0.250L = 36.26×10⁻² mol/L

8 0
3 years ago
If the pressure of a gas sample is quadrupled and the absolute temperature is doubled, by what factor does the volume of the sam
Natasha_Volkova [10]

Answer:

D) 1/2

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given,

P₂ = 4P₁

T₂ = 2T₁

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{P_1}\times {V_1}}{T_1}=\frac {{4\times P_1}\times {V_2}}{2\times T_1}

V_2=\frac{1}{2}\times V_1

<u>The volume change by half of the original.</u>

7 0
3 years ago
Read 2 more answers
Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou
lesya [120]
First, let's compute the number of moles in the system assuming ideal gas behavior. 

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>
3 0
3 years ago
Some one please help me name the following compound CsCrO4​
lozanna [386]

Answer:

Cs is cesium and CrO₄ is chromate so CsCrO₄ is cesium chromate.

8 0
3 years ago
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