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3 years ago

How could you cause a chemical change to vinegar?

1 answer:

3 0

Answer: Any chemical reaction is an example of a chemical change. Examples include: Combining baking soda and vinegar (which bubbles off carbon dioxide gas)Jan 13, 2020

Explanation:

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URGENT PHYSICS QUESTION WILL GIVE BRAINLIEST

Morgarella [4.7K]

Answer:

7.2V

Explanation:

Find the equivalent resistance:

Req = 10 ohms + 15 ohms = 25 ohms

Use ohm's law to find the current:

V = IR

12V = I(25 ohms)

I = .48 amps

Multiple the current with the value of R2 to get the voltage drop:

.48amps x 15 ohms = 7.2V

8 0

3 years ago

According to a general theory of crime, individuals who engage in crime are also likely to engage in other risky behaviors, for

babymother [125]

Answer:

construct validity

Explanation:

According to my research on studies conducted by various psychologists, I can say that based on the information provided within the question it seems that the researcher is using construct validity. This is the act of measuring or validating what the extent to which a claim is true. In this situation since the claim states that people involved in crimes tend to do speed and drugs, then the researcher compares the criminals responses to those areas to test the validity of the claim.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

3 years ago

NEED HELP ASAP

Dafna11 [192]

Answers:

a) -2.54 m/s

b) -2351.25 J

Explanation:

This problem can be solved by the <u>Conservation of Momentum principle</u>, which establishes that the initial momentum $p_{o}$ must be equal to the final momentum $p_{f}$ :

$p_{o}=p_{f}$ (1)

Where:

$p_{o}=m_{1} V_{o} + m_{2} U_{o}$ (2)

$p_{f}=(m_{1} + m_{2}) V_{f}$ (3)

$m_{1}=110 kg$ is the mass of the first football player

$V{o}=-7 m/s$ is the velocity of the first football player (to the south)

$m_{2}=75 kg$ is the mass of the second football player

$U_{o}=4 m/s$ is the velocity of the second football player (to the north)

$V_{f}$ is the final velocity of both football players

With this in mind, let's begin with the answers:

a) Velocity of the players just after the tackle

Substituting (2) and (3) in (1):

$m_{1} V_{o} + m_{2} U_{o}=(m_{1} + m_{2}) V_{f}$ (4)

Isolating $V_{f}$ :

$V_{f}=\frac{m_{1} V_{o} + m_{2} U_{o}}{m_{1} + m_{2}}$ (5)

$V_{f}=\frac{(110 kg)(-7 m/s) + (75 kg) (4 m/s)}{110 kg + 75 kg}$ (6)

$V_{f}=-2.54 m/s$ (7) The negative sign indicates the direction of the final velocity, to the south

b) Decrease in kinetic energy of the 110kg player

The change in Kinetic energy $\Delta K$ is defined as:

$\Delta K=\frac{1}{2} m_{1}V_{f}^{2} - \frac{1}{2} m_{1}V_{o}^{2}$ (8)

Simplifying:

$\Delta K=\frac{1}{2} m_{1}(V_{f}^{2} - V_{o}^{2})$ (9)

$\Delta K=\frac{1}{2} 110 kg((-2.5 m/s)^{2} - (-7 m/s)^{2})$ (10)

Finally:

$\Delta K=-2351.25 J$ (10) Where the minus sign indicates the player's kinetic energy has decreased due to the perfectly inelastic collision

6 0

3 years ago

The diameter of an atom is 1.1×10−10m and the diameter of its nucleus is 1.0×10−14m. Part A What percent of the atom's volume is

77julia77 [94]

To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,

$\% Percent = \frac{V_{nucleus}}{V_{atom}}*100$