Answer:
The value is
Explanation:
From the question we are told that
The period of the asteroid is
Generally the average distance of the asteroid from the sun is mathematically represented as
Here M is the mass of the sun with a value
G is the gravitational constant with value
=>
Generally
So
=>
=>
Answer:
m = 35.98 Kg ≈ 36 Kg
Explanation:
I₀ = 125 kg·m²
R₁ = 1.50 m
ωi = 0.600 rad/s
R₂ = 0.905 m
ωf = 0.800 rad/s
m = ?
We can apply The law of conservation of angular momentum as follows:
Linitial = Lfinal
⇒ Ii*ωi = If*ωf <em>(I)</em>
where
Ii = I₀ + m*R₁² = 125 + m*(1.50)² = 125 + 2.25*m
If = I₀ + m*R₂² = 125 + m*(0.905)² = 125 + 0.819025*m
Now, we using the equation <em>(I) </em>we have
(125 + 2.25*m)*0.600 = (125 + 0.819025*m)*0.800
⇒ m = 35.98 Kg ≈ 36 Kg
Answer:
Explanation:
Initial velocity (u) = 2 m/s
Displacement (s) = 2.5 m
Acceleration due to gravity(a)=9.81m/s^2
Final velocity (v) = ?
Now, formula is given by
v² = u² + 2×a×s
v² = 2² + 2×9.81×2.5
v² = 4 + 49.05
v² = 53.05
v = √53.05
v = 7.3 m/s
Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.
Explanation: Please see the attachments below