Answer:
f(- 2) = - 20
Step-by-step explanation:
Using synthetic division
- 2 | 4 1 - 3 2
4 - 8 14 - 22
------------------------
- 7 11 - 20 ← f(- 2) = - 20
Answer:
324,632 possible combinations
Step-by-step explanation:
We are looking for the amount of combinations of 5 students we can have in a class of 35 students. We write this as 35_C_5. The formula for finding the number of combinations of x objects from a set of y objects is x_C_y =
.
Then we have:
35_C_5 = 
--- expand
--- simplify
324,632 --- simplify
324,632 possible combinations
Answer:
Answer:So the maximum value of P is 138.Step-by-step explanation:
P(0,0)= 24(0) + 30(0) =0
P(0,1)= 24(0) + 30(1) =30
P(5,0)= 24(5) + 30(0) =120
P(2,3) =24(2) + 30(3) = 138I also