PLEASE HELP (must show work) Show all work to factor x4

Approximately how fast does a car have to travel if it can travel from North Carolina to New York in 12 hours

garri49 [273]

The distance is approximately 703 kilometers.
To travel that in 12 hours, a car has to go at 703/12=58.583 km/h

3 0

3 years ago

4x + 108 = 144 what is the value of x

ivann1987 [24]

Here is the correct answer.

4x + 108 = 144(equation)
-108 -108 (Subtract 108 both sides)
4x = 36 (simplify)
/4 /4 (divide by 4)
x = 9 (Answer)

7 0

3 years ago

Read 2 more answers

Math 2 Of high school

Daniel [21]

Answer:

B. BC = 18 so ∆ABC ～ ∆DEF by SAS

Step-by-step explanation:

$\bf \cfrac{AB}{DE} = \cfrac{BC}{EF}$

$\bf \cfrac{15}{10} = \cfrac{BC}{12}$
$\bf \cfrac{3}{2} = \cfrac{BC}{12}$
$\bf BC = \cfrac{3}{2} \times 12$
$\bf 3 \times 6$
$\bf BC = 18$
$\bf \angle B = \angle \: E$

So, ∆ABC ～ ∆DEF by SAS.

7 0

2 years ago

Picture shown below help

Alex_Xolod [135]

Answer:

measure of angle 2 and angle 3 are both 97

Step-by-step explanation:

angle 2 and angle 3 are vertical angles

6 0

3 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

3 years ago

PLEASE HELP (must show work) Show all work to factor x4 - 17x2 + 16 completely.