A developing story hope it helped
Answer:
Semantic memory is a category of long-term memory that involves the recollection of ideas, concepts and facts commonly regarded as general knowledge. Examples of semantic memory include factual information such as grammar and algebra.
Answer:
Explanation:
wave length of light λ = 623 x 10⁻⁹ m .
Distance of screen D = 76.5 x 10⁻² m
width of slit = d
Distance on the screen between the second order minimum and the central maximum = 2 λ D / d
1.11 x 10⁻² = (2 x 623 x 10⁻⁹ x 76.5 x 10⁻² )/ d
d = ( 2 x 623 x 10⁻⁹ x 76.5 x 10⁻²) / 1.11 x 10⁻²
= 85872.97 x 10⁻⁹
= 85.87297 x 10⁻⁶
= 85.87 μm
width a of the slit is = 85.87 μm
Answer:
![4.01\cdot 10^{-7} m](https://tex.z-dn.net/?f=4.01%5Ccdot%2010%5E%7B-7%7D%20m)
Explanation:
When an electromagnetic wave passes through the interface between two mediums, it undergoes refraction, which means that it bents and its speed and its wavelength change.
In particular, the wavelength of an electromagnetic wave in a certain medium is related to the index of refraction of the medium by:
![\lambda=\frac{\lambda_0}{n}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B%5Clambda_0%7D%7Bn%7D)
where
is the wavelength in a vacuum (air is a good approximation of vacuum)
n is the refractive index of the medium
In this problem:
is the original wavelength of the wave
n = 1.47 is the index of refraction of corn oil
Therefore, the wavelength of the electromagnetic wave in corn oil is:
![\lambda=\frac{5.89\cdot 10^{-7}}{1.47}=4.01\cdot 10^{-7} m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B5.89%5Ccdot%2010%5E%7B-7%7D%7D%7B1.47%7D%3D4.01%5Ccdot%2010%5E%7B-7%7D%20m)
Answer:
3 km/h
Explanation:
Let's call the rowing speed in still water x, in km/h.
Rowing speed in upstream is: x - 2 km/h
Rowing speed in downstream is: x + 2 km/h
It took a crew 9 h 36 min ( = 9 3/5 = 48/5) to row 8 km upstream and back again. Therefore:
8/(x - 2) + 8/(x + 2) = 48/5 (notice that: time = distance/speed)
Multiplying by x² - 2², which is equivalent to (x-2)*(x+2)
8*(x+2) + 8*(x-2) = (48/5)*(x² - 4)
Dividing by 8
(x+2) + (x-2) = (6/5)*(x² - 4)
2*x = (6/5)*x² - 24/5
0 = (6/5)*x² - 2*x - 24/5
Using quadratic formula
![x = \frac{2 \pm \sqrt{(-2)^2 - 4(6/5)(-24/5)}}{2(6/5)}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B2%20%5Cpm%20%5Csqrt%7B%28-2%29%5E2%20-%204%286%2F5%29%28-24%2F5%29%7D%7D%7B2%286%2F5%29%7D)
![x = \frac{2 \pm 5.2}{2.4}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B2%20%5Cpm%205.2%7D%7B2.4%7D)
![x_1 = \frac{2 + 5.2}{2.4}](https://tex.z-dn.net/?f=x_1%20%3D%20%5Cfrac%7B2%20%2B%205.2%7D%7B2.4%7D)
![x_1 = 3](https://tex.z-dn.net/?f=x_1%20%3D%203)
![x_2 = \frac{2 - 5.2}{2.4}](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B2%20-%205.2%7D%7B2.4%7D)
![x_2 = -1\; 1/3](https://tex.z-dn.net/?f=x_2%20%3D%20-1%5C%3B%201%2F3)
A negative result has no sense, therefore the rowing speed in still water was 3 km/h