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s344n2d4d5 [400]
3 years ago
10

Is -3 a solution to equation 3x -5 = 4+ 2x

Physics
1 answer:
Elodia [21]3 years ago
5 0

Answer:

No!

Explanation:

The correct answer is x = 9.

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A manager at a local bank analyzed the relationship between monthly salary and three independent variables: length of service (m
Readme [11.4K]

Answer:

a

Explanation:

8 0
3 years ago
What is an example of a high amplitude sound, and an example of a low amplitude sound? 
Sergeu [11.5K]
High amplitude sound would be music, radio, or earthquakes.
Low amplitude sound would be a breeze or wind.
7 0
3 years ago
Read 2 more answers
hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check
leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

F=I(L\times B)

or

F=ILB\ sin\theta

Where

\theta is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

  1. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
  2. .The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
  3. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
7 0
3 years ago
dopasuj wartości pracy z ramki do przedstawionych sytuacji ,a nastepnie wyraż te prace w dżulach uwaga jedna wartośc pracy nie b
Eduardwww [97]

Answer:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Explanation:

Całą część pytania można znaleźć na poniższym schemacie.

Z diagramu załączonego poniżej; mamy

A - samolot lotniczy

B - dźwig

C - podnoszenie ciężarów

Wszyscy to wiemy ;

1kJ = 1000 J

1MJ = 1000000 J

Mamy cztery opcje; i.e 200 MJ, 800 kJ, 1.6 kJ  and 250 mJ

Z czterech opcji można wykluczyć 250 mJ, ponieważ jest to 0,25 J, co przedstawia bardzo niską energię w porównaniu z trzema warunkami pokazanymi na schemacie.

Więc:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Największą pracę wykona samolot. Jest tak, ponieważ ma bardzo dużą masę i bardzo dużą prędkość. W związku z tym istnieje potrzeba wytworzenia ogromnej ilości ciepła i energii.

Z drugiej strony żuraw może podnieść ładunek o wiele większy i przewyższa ciężar ciężaru, więc praca wykonywana przez dźwig musi być zdecydowanie większa niż praca ciężarka.

3 0
3 years ago
Q.20
Svetllana [295]

Answer:

what are you talking about

6 0
3 years ago
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