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Lelu [443]
3 years ago
7

What is the electromagnetic spectrum used for?

Physics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

The electromagnetic spectrum is used for identifying what type a wave is. For example, a  wave with a very low frequency would be a radio wave, and a wave with a very high wavelength would be a gamma wave.

Let me know if this helps!

stiks02 [169]3 years ago
5 0

Answer:  Astronomers use the entire electromagnetic spectrum to observe a variety of things. Radio waves and microwaves – the longest wavelengths and lowest energies of light – are used to peer inside dense interstellar clouds and track the motion of cold, dark gas

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Natalija [7]
The answer is 1. 4 is incorrect because you can't really decrease the mass of the driver. 3 is incorrect because accelerating the driver would cause more damage than not. 2 is incorrect because decreasing the distance would only cause more damage. 1 is correct because by increasing the length of time the force acts on the driver helps reduce the speed of the driver and cause the drive to sustain less injuries. Hope that helps.
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What kind of charging is occurring in the first part of the video (when the
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Static charge is occurring
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Large sections of troposphere with same temperature and humidity is called
77julia77 [94]

Answer:

air mass

Explanation:

These are known as the air mass. However, the air mass results in sever storms at times. The storms are known as tornadoes. The storms are also very powerful as they can cause the distraction of everything in their path.In addition, the large sections result in the different types of air masses. These air masses are known as:

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7 0
3 years ago
After a 0.320-kg rubber ball is dropped from a height of 19.0 m, it bounces off a concrete floor and rebounds to a height of 15.
GarryVolchara [31]

Answer:

Imp = 11.666\,\frac{kg\cdot m}{s}

Explanation:

Speed experimented by the ball before and after collision are determined by using Principle of Energy Conservation:

Before collision:

(0.32\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (19\,m) = \frac{1}{2}\cdot (0.320\,kg)\cdot v_{A}^{2}

v_{A} \approx 19.304\,\frac{m}{s}

After collision:

\frac{1}{2}\cdot (0.320\,kg)\cdot v_{B}^{2} = (0.32\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (15\,m)

v_{B} \approx 17.153\,\frac{m}{s}

The magnitude of the impulse delivered to the ball by the floor is calculated by the Impulse Theorem:

Imp = (0.32\,kg)\cdot [(17.153\,\frac{m}{s} )-(-19.304\,\frac{m}{s} )]

Imp = 11.666\,\frac{kg\cdot m}{s}

5 0
3 years ago
Read 2 more answers
Constants Periodic Table A seesaw has a mass of 50 kg, a length of 3.0 m, and a fulcrum beneath its midpoint. It is balanced whe
andrew-mc [135]

Answer:

Solution is attached below.

Explanation:

3 0
3 years ago
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