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Vika [28.1K]
2 years ago
7

The answer to the problem: 3.6 x 4.639 + 5.831 = _____, written to the correct number of significant digits is:

Chemistry
1 answer:
natka813 [3]2 years ago
4 0

Answer:

3.6 x 4.639 + 5.831 = 2000

Explanation:

In this problem, we need to find the value of 3.6 x 4.639 + 5.831.

Here, 3.6 has 2, 4.639 and 5.831 has 4 significant figures.

We can use BODMAS RULE to find it as follows :

3.6 x 4.639 + 5.831 = (3.6 x 4.639) + 5.831

= 2325.96 + 5.831

in significant gigure,

= 2300 + 5.831

= 2305.831

In one significant figure,

= 2000

Hence, the answer of the problem is 2000.

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Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu
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Answer:

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Explanation:

Given that:

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r = \dfrac{a}{2\sqrt{2}}

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to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}

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mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

mass\  of\ atom =\dfrac{ atomic \ mass}{Avogadro  \  number}

mass\  of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}

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mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4

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