All categories

2 years ago

The answer to the problem: 3.6 x 4.639 + 5.831 = _____, written to the correct number of significant digits is:

Chemistry

1 answer:

natka813 [3]2 years ago

4 0

Answer:

3.6 x 4.639 + 5.831 = 2000

Explanation:

In this problem, we need to find the value of 3.6 x 4.639 + 5.831.

Here, 3.6 has 2, 4.639 and 5.831 has 4 significant figures.

We can use BODMAS RULE to find it as follows :

3.6 x 4.639 + 5.831 = (3.6 x 4.639) + 5.831

= 2325.96 + 5.831

in significant gigure,

= 2300 + 5.831

= 2305.831

In one significant figure,

= 2000

Hence, the answer of the problem is 2000.

You might be interested in

Which branch of chemistry would be used to make steel?

Tpy6a [65]

Answer:

the five major branches of chemistry are organic, inorganic, analytical, physical, and biochemistry.

5 0

3 years ago

How to I answer this question! Not looking for the answers for the question just how to solve it myself!

Mrac [35]

I have not taken Chemistry in a year but I remember that if you look at a periodic table there are certain sections for polar and non polar elements. I dont know if you have learned that yet

7 0

3 years ago

Read 2 more answers

which parts of animals are rarely preserved unburied because scavengers eat them and bacteria decompose them? hard shells soft s

katovenus [111]

Soft skulls. hope this helps

4 0

3 years ago

Read 2 more answers

'Let this cup pass from you, eh?'

LuckyWell [14K]

Answer:

“'Let this cup pass from you, eh? '” This quote is an allusion to Christ in the Garden of Gethsemane before he is crucified. ... This quote alludes to Hitler who is the Nazi ruler in Germany.

6 0

2 years ago

An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.

____ [38]

Answer:

(a) Density of the air = 1.204 kg/m3

(b) Pressure = 93772 Pa or 0.703 mmHg

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

$\rho_{air}=\frac{P}{R*T}$

First, we change the units of P to Pa and T to deg K:

$P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K$

Then we have

$\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}$

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

$PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg$

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

$F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N$

7 0

2 years ago