3 years ago

AYe PeEpS iF yOu GiVe Me A wEriD aNsWeR ImA rEeEeeEeEpOrT iT :D

Physics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

Tt tT

tT tt

Explanation:

the rest I pretty sure don't understand

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A dripping water faucet steadily releases drops 1.0 s apart. As these drops fall, does the distance between them increase, decre

ololo11 [35]

Answer:

Distance between them increase

Explanation:

The position S of the water droplet can be determined using equation of motion

$S=ut+\frac{1}{2} at^2$

where $u$ is the initial velocity which is zero here

$t$ is time taken, $a$ is acceleration due to gravity

the position of first drop after time $t$ is given by

$S_{1} =0 \times t+ \frac{1}{2} at^2=\frac{1}{2} at^2............(1)$

the position of next drop at same time is

$S_{2} =\frac{1}{2} a(t-1)^2 = \frac{1}{2} a(t^2+1-2t)............(2)$

distance between them is $S_{1} -S_{2}$ is $a(t-1)$

from the above the difference will increase with the time

3 0

3 years ago

A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area

Airida [17]

For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
$p_1 = p_2$
which becomes
$\frac{F_1}{A_1}= \frac{F_2}{A_2}$
where
$F_1=3600 N$ is the force on the first piston
$A_1=0.030 m^2$ is the area of the first piston
$F_2$ is the force on the second piston
$A_2=0.015 m^2$ is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
$F_2=F_1 \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N$

7 0

3 years ago

Read 2 more answers

I need someone to give me 2 answers,

yanalaym [24]

Uh.. what's the question..?

8 0

3 years ago

PLZ help this should be super easy

Ugo [173]

The answer is number (3) if am wrong am sry

4 0