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3 years ago

AYe PeEpS iF yOu GiVe Me A wEriD aNsWeR ImA rEeEeeEeEpOrT iT :D

Physics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

Tt tT

tT tt

Explanation:

the rest I pretty sure don't understand

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An object with a temperature of 0 Kelvin would not emit radiation. a. True b. False

dem82 [27]

That's true.
Radiation always carries energy.
An object at 0 K doesn't have any.

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Clothes dryer uses about 3:00 amps of current from a 240-volt line how much power does it use

kirill115 [55]

Electrical power is defined as

P = I * V

I = 3 amperes

V = 240 volts

Power = 3 * 240

Power = 720 Watts. Answer

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3 years ago

I WILL MARK YOU THE BRAINLIEST NO LINKS What goes were put them in the correct place

PIT_PIT [208]

Answer:

Fluid fricton goes to Static friction and sliding friction goes to rolling friction

Explanation:

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3 years ago

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The 20 kg at angle of 53⁰ in an inclined plane is realsed from rest the coefficient of friction bn the block and the inclined pl

Scorpion4ik [409]

Given :-

A 20kg block at an angle 53⁰ in an inclined plane is released from rest .
$\mu_s = 0.3 \ \& \ \mu_k = 0.2$

To Find :-

Would the block move ?
If it moves what is its speed after it has descended a distance of 5m down the plane .

Solution :-

For figure refer to attachment .

So the block will move if the angle of the inclined plane is greater than the angle of repose . We can find it as ,

$\longrightarrow \theta_{repose}= tan^{-1}(\mu_s)$

Substitute ,

$\longrightarrow \theta_{repose}= tan^{-1}( 0.2)$

Solve ,

$\longrightarrow\underline{\underline{\theta_{repose}= 16.6^o }}$

Hence ,

$\longrightarrow\theta_{plane}>\theta_{repose}$

Hence the block will slide down .

Now assuming that block is released from the reset , it's initial velocity will be 0m/s .

And the net force will be ,

$\longrightarrow F_n = mgsin53^o - \mu_k N$

Substitute, N = mgcos53⁰ ( see attachment)

$\longrightarrow ma_n = mgsin53^o - \mu_k mgcos53^o$

Take m as common,

$\longrightarrow\cancel{m }(a_n) = \cancel{m}( gsin53^o - \mu gcos53^o)$

Simplify ,

$\longrightarrow a_n = gsin53^o - \mu_k g cos53^o$

Substitute the values of sin , cos and g ,

$\longrightarrow a_n = 10( 0.79 - 0.2 (0.6))$

Simplify ,

$\longrightarrow a_n = 10 ( 0.79 - 0.12 ) \\\\ \longrightarrow a_n = 10 (0.67)\\\\ \longrightarrow \underline{\underline{a_n = 6.7 m/s^2}}$

Now using the Third equation of motion namely,

$\longrightarrow2as = v^2-u^2$

Substituting the respective values,

$\longrightarrow2(6.7)(5) = v^2-(0)^2$

Simplify and solve for v ,

$\longrightarrow v^2 = 67 m/s\\\\\longrightarrow v =\sqrt{67} m/s \\\\\longrightarrow\underline{\underline{ v = 8.18 m/s }}$

Hence the velocity after covering 5m is 8.18 m/s .

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3 years ago

1. In a series circuit, if one bulb goes out the other blubs will stay lit.

RideAnS [48]

I think is False
I think is False

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