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chubhunter [2.5K]
3 years ago
8

PAST DUE ASSIGNMENT HELLPPPPP!!

Chemistry
2 answers:
leonid [27]3 years ago
5 0

Answer:

What was the assignment? There's nothing attached, my guy

Explanation:

babunello [35]3 years ago
5 0

Answer: Okay What is the assignments?

Explanation:

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What is the mass of KOH found in a 785 mL of a 1.43 M solution of KOH
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Molarity is defined as the ratio of number of moles to the volume of solution in litres.

The mathematical expression is given as:

Molarity = \frac{Number of moles}{volume of solution in litres}

Here, molarity is equal to 1.43 M and volume is equal to 785 mL.

Convert mL into L

As, 1 mL = 0.001 L

Thus, volume = 785\times 0.001 = 0.785 L

Rearrange the formula of molarity in terms of number of moles:

Number of moles =molarity\times volume of solution in litres

n = 1.43 M \times 0.785 L

= 1.12255 mole

Now,  Number of moles  = \frac{mass in g}{molar mass}

Molar mass of potassium hydroxide  = 56.10 g/mol

1.12255 mole  = \frac{mass in g}{56.10 g/mol}

mass in g = 1.12255 mole\times 56.10 g/mol

= 62.97 g

Hence, mass of KOH = 62.97 g



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Which statement is true about molarity and percent by mass? (3 points)
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