Jenny puts the ph paper and lines it up PH SCALE to find how strong the solution.
Answer:
R aluminium = 2.63x10^-6 Ω*cm
Rcopper = 1.7 x10^-6 Ω*cm
I would use Cu as interconnections in advanced CMOS nodes.
Explanation:
the conductivity formula equals:
σ = n*g*u
n = carrier concentration
u = mobility
g = charge of carrier
The resistivity is equal to:
R = 1/σ
For the aluminium, we have:
g = 1.602x10^-19 C
R = 1/(1.98x10^23 * 1.602x10^-19 * 12 = 2.63x10^-6 Ω*cm
For copper:
R = 1/(8.5x10^22 * 1.602x10^-19 * 43.2) = 1.7 x10^-6 Ω*cm
According to the calculations found for both resistivities, I would use Cu as interconnections in advanced CMOS nodes, since copper has a lower resistivity and therefore, copper conducts electricity better.
It would most likely be a observation or hypothesis
