Answer:
part 1
3) 5.47 molecules
4) 11.15 moles
5) 2.95 × 10^23 molecules
6) 7670.9g
part2
1) 216000g
2) 5.71 molecules
3) 0.18 moles
4) 737.40g
5) 2.89×10^23 molecules
Explanation:
part 1
3) number of moles = (6.02 × 10^23)/11.0
=5.47molecules.
4) moles= (6.02 × 10^23)/(5.40×10^23)
= 11.15 moles
5) molar mass of NH3= 14+(3×1)= 14+3=17
number of molecules= (6.02 × 10^23) × 17/35
= (6.02 × 10^23)× 0.49 =2.95 × 10^23 molecules
6) molar mass of N2I6= (2×14) + (6×127)
= 28+762= 790g/mol
mass= 790 × (6.02 × 10^23)/(6.20×10^22)
=790× 9.71= 7670.9g
part 2
1) molar mass of CuBr= 64+80= 144g/mol
mass= 1500 × 144= 216000g
2) molecules = (6.02 × 10^23)/1.055
= 5.71 molecules
3) moles = (6.02 × 10^23)/(3.35×10^24)
= 0.18 moles
4) molar mass of SiO2= 28+ (2×16)= 28+32
=60gmol
mass= 60 × (6.02 × 10^23)/(4.90×10^22)
= 60× 12.29= 737.40g
5) molar mass of CH4= 12+(4×1)= 12+4=16g/mol
number of molecules= (6.02 × 10^23) × 16/33.6
= (6.02 × 10^23)× 0.48
= 2.89×10^23 molecules
I believe it's two part hydrogen and one part oxygen (H20)
<h2>Answer:</h2>
A basic salt or alkali sat is any salt that hydrolyzes to form a basic solution.
<h3>Explanation:</h3>
In simple terms, It is a salt which is when dissolved in water form a solution of PH less than 7.
It contains amounts of both hydroxide and other anions.
White lead is an example. It is basic lead carbonate, or lead carbonate hydroxide.
<em>Answer :</em> C - 1.02 x 10²³
<em>Explanation ;</em>
1 molecule of Al(NO₃)₃ has 3 N atoms.
Al(NO₃)₃ → Al + 3N + 9O
Moles (mol) = Mass (g) / Molar mass (g/mol)
Mass of Al(NO₃)₃ = 12 g
Molar mass of Al(NO₃)₃ = (27 + 14 x 3 + 16 x 9) g/mol
= 213 g/mol
Mass of Al(NO₃)₃ = 12 g / 213 g/mol
= 0.0563 mol
The stoichiometric ratio between Al(NO₃)₃ compound and N atoms is 1 : 3.
Hence,
the moles of N atoms = moles of Al(NO₃)₃ x 3
= 0.0563 mol x 3
= 0.1689 mol
According to the Avogadro constant,
1 mol of substance = 6.02 x 10²³ particles
Hence, N atoms in the 12 g of Al(NO₃)₃ = 0.1689 mol x 6.02 x 10²³ mol⁻¹
= 1.016778 x 10²³
= 1.02 x 10²³
