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3 years ago

What location is 90 degrees away from the equator?

2 answers:

4 0

C) both A and B

Each parallel measures one degree north or south of the Equator, with 90 degrees north of the Equator and 90 degrees south of the Equator
Hope this helps!

Nutka1998 [239]3 years ago

4 0

<h2>Answer:</h2><h3>C) Both A and B</h3><h2>Explanation:</h2><h3>The axis of 0 degrees latitude is known as the Equator. With 90 degrees north of the Equator and 90 degrees south of the Equator, each parallel measures one degree north or south of the Equator. The North Pole is 90 degrees north latitude, and the South Pole is 90 degrees south latitude.</h3>

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Match the definition with the correct vocab word. - Numbers to Names

sergij07 [2.7K]

Answer:

1. Matter

2. Atom

3. Proton

4. Nucleus

5. Electron

6.Neutron

3 0

3 years ago

What mass of iron is needed to react with 16.0 grams of sulfur

scoray [572]

Answer: 28 grams of iron is needed to react with 16.0 grams of sulfur

Explanation: Please see the attachments below

8 0

3 years ago

A titration reaction requires 38.20 mL phosphoric acid solution to react with 71.00 mL of 0.348 mol/L calcium hydroxide to reach

NARA [144]

1a. The balanced equation for the reaction is:

1b. The number of mole of Ca(OH)₂ is 0.0247 mole

1c. The number of mole of H₃PO₄ is 0.0165 mole.

1d. The concentration of H₃PO₄ is 0.432 mol/L

2. The new concentration of the H₃PO₄ solution is 0.0432 mol/L

<h3>1a. The balanced equation for the reaction</h3>

<u>3</u>Ca(OH)₂ + <u>2</u>H₃PO₄ —> Ca₃(PO₄)₂ + <u>6</u>H₂O

<h3>1b. Determination of the mole of Ca(OH)₂</h3>

Volume of Ca(OH)₂ = 71 mL = 71 / 1000 = 0.071 L

Concentration of Ca(OH)₂ = 0.348 mol/L

Mole = Concentration × Volume

Mole = 0.348 × 0.071

<h3>1c. Determination of the mole of H₃PO₄. </h3>

3Ca(OH)₂ + 2H₃PO₄ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

3 moles of Ca(OH)₂ reacted with 2 moles of H₃PO₄.

Therefore,

0.0247 moles of Ca(OH)₂ will react with = $\frac{0.0247 * 2}{3}$ = 0.0165 mole of H₃PO₄.

Thus, the number of mole of H₃PO₄ is 0.0165 mole

<h3>1d. Determination of the concentration of H₃PO₄</h3>

Volume of H₃PO₄ = 38.20 mL = 38.20/ 1000 = 0.0382 L

Mole of H₃PO₄ = 0.0165 mole

<h3>Concentration of H₃PO₄ =?</h3>

$Concentration = \frac{mole}{volume} \\\\Concentration = \frac{0.0165}{0.0382}$

<h3>Concentration of H₃PO₄ = 0.432 mol/L</h3>

<h3>2. Determination of the new concentration of the H₃PO₄ solution.</h3>

Initial Volume (V₁) = 10 mL

Initial concentration (C₁) = 0.432 mol/L

New volume (V₂) = 100 mL

<h3>New concentration (C₂) =?</h3>

The new concentration of the H₃PO₄ solution can be obtained as follow:

0.432 × 10 = C₂ × 100

4.32 = C₂ × 100

Divide both side by 100

C₂ = $\frac{4.32}{100}\\$

Therefore, the new concentration of the H₃PO₄ solution is 0.0432 mol/L

Learn more:

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3 0

3 years ago

The pOH of a solution is 9.21. Calculate the hydrogen ion concentration of the solution. Be sure to report your answer to the co

11Alexandr11 [23.1K]

Answer:

[OH-] = 6.17 *10^-10

Explanation:

Step 1: Data given

pOH = 9.21

Step 2: Calculate [OH-]

pOH = -log [OH-] = 9.21

[OH-] = 10^-9.21

[OH-] = 6.17 *10^-10

Step 3: Check if it's correct

pOH + pH = 14

[H+]*[OH-] = 10^-14

pH = 14 - 9.21 = 4.79

[H+] = 10^-4.79

[H+] = 1.62 *10^-5

6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14

3 0

3 years ago

What is the frequency of a 6.14 x 10^4 m wave

andrew11 [14]

From the information give, I'm going to assume the wave is in a vacuum...

You use the equation: f= $\frac{C}{Wavelength}$ where c is the constant for speed of light ( $3.00 x 10^{8}$

so f= $\frac{3.00x10^{8}}{6.14x10^{4}}$

f= 4.89 x $10^{3}$ Hz (approximately)

7 0

3 years ago