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Mandarinka [93]
3 years ago
6

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J

or

Q = 282,000 J

So, the required heat is 282,000 J .

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if it is true that the net charge in the universe does not change, how is it ever possible to charge an object that was initiall
olga55 [171]

By transferring electrical charges from one object to another

Explanation:

The law of conservation of electric charge states that the total electric charge of the universe is constant, therefore no charge can be created or destroyed, but only transferred.

Indeed, when an object is charged, this is due to the fact that charge carriers (typically electrons) are transferred to/from the object.

Consider an object initially neutral: this means that the object has initially an equal amount of positive charges (protons) and negative charges (electron).

Later, if we remove electrons from the object, then it will remain with an excess of protons: therefore, it will be positively charged. However, the electrons have not disappeared: simply, they have been moved somewhere else (on another object, for example, which will become negatively charged: so, the total net charge will still be zero).

Similarly, if we add electrons to the object, it will become negatively charged: however, the electrons have been removed from another object which is now positively charged, so the net charge still has not changed.

Learn more about electric charges:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

8 0
3 years ago
Suppose you have a 34.9 m length of copper wire. If the wire is wrapped into a solenoid 0.240 m long and having a radius of 0.05
Nadusha1986 [10]

Answer:

the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.

Explanation:

Given;

length of the wire, = 34.9 m

length of solenoid, L = 0.24 m

radius of the solenoid, r = 0.051 m

current in the solenoid, I = 11.0 A

The number of turns of the wire is calculated as follow;

N = \frac{34.9}{2\pi \times 0.051} = 109 \ turns

The strength of the magnetic field inside the solenoid is calculated as follows;

B = \mu_0 (\frac{N}{L} )I\\\\B = 4\pi \times 10^{-7} \times (\frac{109}{0.24} )\times 11.0 \\\\B = 6.278 \times 10^{-3} \ T

Therefore, the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.

8 0
3 years ago
Please help, I really don't know
zubka84 [21]

circular motion.

cent acc = r omega^2 ... omega is ang vel ... omega=2pi/T ,,,

9.8=rx(2pi/T)^2

if r is known, solve for T


7 0
4 years ago
If 2000 kg cannon fires 2 kg projectile having muzzle velocity 200 m/s then the KINETIC ENERGY of the projectile will be ("E4" m
nordsb [41]

Answer:

K=4\times 10^4\ J

Explanation:

Given that,

Mass of cannon is,M =  2000 kg

Mass of projectile, m = 2 kg

Velocity of the projectile, v = 200 m/s

We need to find the kinetic energy of the projectile. We know that the formula for the kinetic energy of an object is given by :

K=\dfrac{1}{2}mv^2\\\\\text{Putting all the values, we get}\\\\K=\dfrac{1}{2}\times 2\times (200)^2\\\\K=40000\ J

or

K=4\times 10^4\ J

So, the kinetic energy of the projectile will be 4\times 10^4\ J.

7 0
3 years ago
If you perform 40 J of work lifting a 10-N box from the floor to a shelf, how high is the shelf?
sweet [91]
The shelf is four meters high

3 0
3 years ago
Read 2 more answers
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