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Mandarinka [93]
2 years ago
6

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
Kitty [74]2 years ago
6 0

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J

or

Q = 282,000 J

So, the required heat is 282,000 J .

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(a)

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Let us take the north direction to be the positive y-axis and the east to be positive x-axis.

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r=\sqrt{x^2+y^2}=41.32km

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\alpha =tan^{-1}(\frac{y}{x})=24.23^o

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