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Mandarinka [93]
3 years ago
6

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J

or

Q = 282,000 J

So, the required heat is 282,000 J .

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0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)

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3 = y₀ − 4.9 t₁²

3 = y₀ − 4.9 (0.412)²

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