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katrin2010 [14]
3 years ago
11

Describe how you could engineer the situation to produce even more friction and heat

Engineering
1 answer:
lana66690 [7]3 years ago
6 0
True the use many abstract power
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Depending on the model, all-electric vehicles can go about _______ miles on a single charge.
Lera25 [3.4K]

Answer:

D

Explanation:

Most electric vehicles can go at least 100.....few, if any, can go 400 or more on a single charge

6 0
2 years ago
A resistance of 30Ω is placed in a circuit with a 90 volt battery. What current flows in the circuit?
Svetlanka [38]

Answer:

30 Amperes

Explanation:

if    V ⇒ voltage

      I ⇒ current

      R ⇒ resistance

V = IR

90 = I x 30

90/30 = I

3 = I

6 0
2 years ago
if two or more resistors are connected in parallel, the total resistance is _ than any single resistor
Andreas93 [3]
Parallel Resistor Equation
If the two resistances or impedances in parallel are equal and of the same value, then the total or equivalent resistance, RT is equal to half the value of one resistor. That is equal to R/2 and for three equal resistors in parallel, R/3, etc.
7 0
3 years ago
Which option identifies the next step Kristin should take to test the design in the following scenario?
Nadusha1986 [10]
The 2d sketch should be right
4 0
3 years ago
Using the AASHTO procedure, determine the thickness required for a base and a surface layer over existing subgrade. The structur
garri49 [273]

Answer:

<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>

Explanation:

structural number = 4.5

stone base course material coefficient = 0.13

hma material layer coefficient = 0.40

drainage coefficient = 0.90

we will use layered analysis procedure to get thickness

D1 >= sN1/a1

when we cross multiply,

sN1 = a1D1 >=sN1

D2 >= -sN2-sN1/a2m2

sN2* + sN1* >= sN2

D3 >= sN3-(sN1*+sN2*)/a2m2

where a1,a2,a3 = layer coefficient

d1 d2 d3 = actual thickness

m2,m3 = coefficient of base

a1 = 0.4

a1 = 0.13

sN = 4.5

m2 = 0.9

D1 >= sN1/a1 = 4.5/0.4

= 11.25

thickness of surface = 12 inches

a1D1 = 0.4x12 = 4.8

we have value of sN2 = 5.5

(5.5 -4.8)/(0.13*0.9)

= 0.7/0.117

= 5.9829 inches

approximately 6 inches

so the pavement will have 12inch HMA surface and 6 inches granular base layer.

7 0
3 years ago
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