<em>Answer:</em>
- Conc. of K+ ions = 0.90 M
- Coc. of SO4∧-2 = 0.45 M
<em>Explanation:</em>
<em>Data Given:</em>
Conc. of H2SO4 = 0.450
As sulphoric acid is a strong electrolyte, it completely dissociate into ions.
H2SO4 ⇆ 2K+ + SO4∧-2
.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.
K2SO4 : K+ K2SO4 : SO4∧-2
1 = 2 1 = 1
0.450 = 2× 0.450 = 0.90 0.450 = 0.450×1 = 0.450
<em> Result:</em>
Conc. of potassium ion will be 0.90M
Coc. of sulphate ions will be 0.45 M
Given :
Volume of NaCl solution 2.5 L .
Molarity of NaCl solution is 0.070 M .
To Find :
How many moles are present in the solution.
Solution :
Let, n be the number of moles.
We know, molarity is given by :
So,
Therefore, number of moles of NaCl is 0.175 moles.
Answer:
The co2 si the e theing for he h2o for the photosysthis of the moon= mass
Explanation:
Answer is: Te (tellurium).
During electron capture, iodine-123 f<span>orm the nearly-stable nuclide tellurium-123.
</span>In beta
plus decay (atomic number Z is decreased by one), a proton is converted to a neutron
and positron and an electron neutrino, so mass <span>number does not
change.
</span>Iodine-123 is a radioactive isotope of iodine used in nuclear medicine imaging.<span>
</span>
Answer:
n = 4678.13 mol
Explanation:
Given data:
Temperature = 21°C
Pressure = 746 mmHg
Volume = 115 m³
Number of moles = ?
Solution:
21+273 = 294 k
746 /760 = 0.982 atm
115×1000 = 115000 L
PV = nRT
n = PV/RT
n = 0.982 atm × 115000 L /0.0821 atm. L. K⁻¹. mol ⁻¹× 294 k
n = 112930 atm. L/24.14 atm. L. mol ⁻¹
n = 4678.13 mol
