Answer: False
Explanation: just took on edge
Answer:
3.64g
Explanation:
Given parameters:
Mass of NH₃ = 18.1g
Mass of Cu₂O = 90.4g
Unknown:
Limiting reactant = ?
Mass of N₂ formed = ?
Solution:
The reaction equation is given as:
Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;
Number of moles =
Molar mass of Cu₂O = 2(63.6) + 16 = 143.2g/mol
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles of Cu₂O =
= 0.13moles
Number of moles of NH₃ =
= 5.32moles
From this reaction;
1 mole of Cu₂O combines with 2 mole of NH₃
So 0.13moles of Cu₂O will combine with 0.13 x 2 mole of NH₃
= 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;
Mass of N₂;
Mass = number of moles x molar mass
1 mole of Cu₂O will produce 1 mole of N₂
0.13 mole of Cu₂O will produce 0.13 mole of N₂
Mass = 0.13 x (2 x 14) = 3.64g
The molecular formula =C₆H₁₂O₆
<h3>Further explanation</h3>
Given
6.00 g of a certain compound X
The molecular molar mass of 180. g/mol
CO₂=8.8 g
H₂O=3.6 g
Required
The molecular formula
Solution
mass C in CO₂ :
= 1.12/44 x 8.8
= 2.4 g
mass H in H₂O :
= 2.1/18 x 3.6
= 0.4 g
Mass O in compound :
= 6-(2.4+0.4)
= 3.2 g
Mol ratio C : H : O
= 2.4/12 : 0.4/1 : 3.2/16
= 0.2 : 0.4 : 0.2
= 1 : 2 : 1
The empirical formula : CH₂O
(CH₂O)n=180 g/mol
(12+2+16)n=180
(30)n=180
n=6
(CH₂O)₆=C₆H₁₂O₆
Answer:
Adding salt to the water increases the density of the solution because the salt increases the mass without changing the volume very much. When you add table salt (sodium chloride, NaCl) to water, the salt dissolves into ions, Na+ and Cl-. The volume increases by a small factor, but the mass increases by a bigger factor.
Explanation: