All categories

2 years ago

How much force is required to accelerate a 800kg car by 15 m/s2

Physics

2 answers:

antoniya [11.8K]2 years ago

4 0

Answer:

12000 N

Explanation:

The equation for Force is:

$Force=mass*acceleration$

We can plug in the given values into the equation:

$Force=800kg*15m/s^2\\Force=12000N$

Tom [10]2 years ago

3 0

Answer:

force=12000

Explanation:

F=m*a aka force equals mass times acceleration so 800*15=12000

You might be interested in

A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T.

sineoko [7]

Answer:10842.33m/s

Explanation:

F=qvBsine

V=f/(qBsine)

V=(3.5×10^-2)÷(8.4×10^-4×6.7×10^-3×sin35)

V=10842.33m/s

5 0

3 years ago

Hello....I need help with this question.

musickatia [10]

Answer:

3.2 m/s²

Explanation:

Acceleration can be calculated as:

v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time)

25 m/s = 9 m/s + a(5 s) (a is unknown)

16 m/s = a(5 s)

a = 3.2 m/s²

We assume that this is a uniform acceleration (meaning that the velocity increases at an equal rate for those 5 seconds).

6 0

3 years ago

Read 2 more answers

A uniform disk of mass 3.25 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum?

shutvik [7]

ANSWER:

0.0562 J

STEP-BY-STEP EXPLANATION:

Angular momentum is expressed in terms of moment of inertia and angular velocity. This is expressed as follows:

$L=I\cdot\omega$

Here, I is the angular momentum and ω is the angular velocity.

Angular momentum is mass time the square of the radius of the object. Moment of inertia for a uniform disk is given as,

$I=\frac{1}{2}m\cdot r^2$

Here, m is the mass of the disk and r is the radius of the disk.

Replacing:

$L=\frac{1}{2}m\cdot r^2\cdot\omega$

Convert the units of angular velocity into rad/s.

$\begin{gathered} \omega=0.55\text{ rev/s}\cdot\frac{2\pi\text{ rad}}{1\text{ rev}} \\ \omega=3.46\text{ rad/s} \end{gathered}$

We replace each data to calculate the angular momentum:

$\begin{gathered} L=\frac{1}{2}\cdot3.25\cdot0.1^2\cdot3.46 \\ L=0.0562 \end{gathered}$

The angular momentum of the uniform disk is 0.0562 J

7 0

1 year ago

A baseball is thrown by the center fielder (from shoulder level) to home plate where it is caught (on the fly at eye level) by t

marishachu [46]

At the highest point of the trajectory the vertical component will have its zero velocity, and the descent caused by the force of gravity will begin.

Since the ball is thrown with a certain speed, the vertical component reaches its highest point (upwards), until returning to the receiver who will receive the ball with the same vertical component but in the opposite direction (downwards).

Therefore the vertical component will have its highest value at launch.

8 0

3 years ago

At a local swimming pool, the diving board is elevated h = 5.5 m above the pool's surface and overhangs the pool edge by L = 2 m

Margaret [11]

Answer:

Part a)

$t = \sqrt{\frac{2h}{g}}$

Part b)

$t = 1.06 s$

Part c)

$L = 4.86 m$

Explanation:

Part a)

The height of the diving board is given as

$h = 5.5 m$

now the speed of the diver is given as

$v_0 = 2.7 m/s$

when the diver will jump into the water then his displacement in vertical direction is same as that of height of diving board

So we will have

$y = v_y t + \frac{1}{2}at^2$

$h = 0 + \frac{1}{2}gt^2$

$t = \sqrt{\frac{2h}{g}}$

Part b)

$t = \sqrt{\frac{2h}{g}}$

plug in the values in the above equation

$t = \sqrt{\frac{2(5.5 m)}{9.81}$

$t = 1.06 s$

Part c)

Horizontal distance moved by the diver is given as

$d = v_0 t$

$d = 2.7 \times 1.06$

$d = 2.86 m$

so the distance from the edge of the pool is given as

$L = 2.86 + 2$

$L = 4.86 m$

4 0

3 years ago

How much force is required to accelerate a 800kg ￼car by 15 m/s2

How much force is required to accelerate a 800kg car by 15 m/s2