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nadezda [96]
3 years ago
11

The photo shows falling water droplets.

Physics
1 answer:
levacccp [35]3 years ago
4 0
I Think The answer is d I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
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You push very hard on a heavy desk, trying to move it. You do work on the desk:
frozen [14]

Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

3 0
3 years ago
A child attempts to roll a ball up a long ramp and it slows as it goes up. If it is released at 2.5 m/s upward and accelerates d
valina [46]

Answer:

-0.7 m/s

Explanation:

Initial velocity (u)= 2.5 m/s

Acceleleration (a)= -0.8 m/s^2

Time taken (t) = 4  seconds

Hence,

v=u+at [1st Equation of motion]

v=2.5+-0.8*4

v=2.5-3.2

v=-0.7 m/s

Note that the negative sign indicates that the ball has changed direction and rolls downwards with gravity

8 0
3 years ago
How does charging by conduction compare with charging by induction?
daser333 [38]
Oppositely charged objects form in induction but not in conduction.
5 0
3 years ago
Read 2 more answers
Yung's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a sc
Lady bird [3.3K]

Answer:

1.082 mm

Explanation:

From the question, we can see that we were given The following

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1.1 m

We know that Y(20) = 10.2 mm = 10.2*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1.1 * 502*10^-9)/10.2*10^-3

d = 1.1*10^-5 / 10.2*10^-3

d = 1.082 mm

Therefore, we can say that the distance of separation between the two slits is 1.082 mm

4 0
4 years ago
NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts. The sup
Finger [1]

Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts. The supply storage area of the lunar outpost, where gravity is 1.63 m/s2, can only support 1 x 10^5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost

Answer:

601,220N

Explanation:

Given that:

Gravity at lunar outpost = 1.63m/s²

Acceleration due to gravity on earth = 9.8m/s²

Supported weight = 1 * 10^5 N

Maximum weight of supplies as measured on earth;

(Ratio of the gravities) * weight of supplies

(9.8m/s² / 1.63m/s²) * (1 * 10^5 N)

6.0122 * (1 * 10^5)

6.0122 * 10^5 N

= 601,220 N

3 0
3 years ago
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