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shutvik [7]
3 years ago
15

How much force would be needed to cause a 4.6kg object to accelerate at 9.2m/s/s? *

Physics
1 answer:
poizon [28]3 years ago
5 0

Answer:

<h2>42.32 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4.6 × 9.2

We have the final answer as

<h3>42.32 N</h3>

Hope this helps you

You might be interested in
A 5.22×104 kg railroad car moves on frictionless horizontal rails until it hits a horizontal spring stopper with a force constan
In-s [12.5K]

To solve this problem we will apply the principles of conservation of energy, for which we have to preserve the initial kinetic energy as elastic potential energy at the end of the movement. If said equality is maintained then we can affirm that,

\text{Initial Energy}=\text{Final Energy}

\frac{1}{2} mv^2=\frac{1}{2} kx^2

Here,

m = mass

k = Spring constant

x = Displacement

v = Velocity

Rearranging to find the velocity,

mv^2 = kx^2

v^2 = \frac{kx^2}{m}

v = \sqrt{\frac{kx^2}{m}}

Our values are,

m = 5.22*10^4kg

k = 4.58*10^5N/m

x = 32cm = 0.32m

Replacing our values we have,

v = \sqrt{\frac{(4.58*10^5)(5.22*10^4)}{0.32}}

v = 2.733*10^5m/s

Therefore the velocity is 2.733*10^5m/s

8 0
4 years ago
What mass of steam at 100°C must be mixed with 490 g of ice at its melting point, in a thermally insulated container, to produce
sukhopar [10]

Answer:

the mass of steam at 100°C must be mixed is 150 g

Explanation:

given information:

ice's mass, m_{i} = 490 g = 0.49 kg

steam temperature, T = 100°C

liquid water temperature, T = 89.0°C

specific heat of water, c_{w} = 4186 J/kg.K = 4.186 kJ/kg.K

latent heat of fusion, L_{f} = 333 kJ/kg

latent heat of vaporization, L_{v} = 2256 kJ/kg

first, we calculate the heat of melted ice to water

Q₁ = m_{i} L_{f}

where

Q = heat

m_{i} = mass of the ice

L_{f}  = latent heat of fusion

thus,

Q₁ = m_{i} L_{f}

    = 0.49 x 333

    = 163.17 kJ

then, the heat needed to increase the temperature of water to 89.0°C

Q₂ = m_{i} c_{w} (89 - 0), the temperature of ice is 0°C

c_{w} = specific heat of water

so,

Q₂ = m_{i} c_{w} (89 - 0)

     = 0.49 x 4.186 x 89

     = 182.55 kJ

so, the heat absorbed by the ice is

Q = Q₁ + Q₂

   = 163.17 + 182.55

   = 345.72 kJ

the temperature of the steam is 100°C, so the mass of the steam is

Q = m_{s}L_{v}  +  m_{s}c_{w} (100 - 89)

Q = m_{s}(L_{v}  +  c_{w} (11))

m_{s} = Q/ [L_{v}  +  c_{w} (11)]

      = 345.72/ [2256 + (4.186 x 11)]

      = 0.15 kg

      = 150 g

5 0
3 years ago
A sound wave takes 0.2 seconds to travel 306 meters.
chubhunter [2.5K]

Answer:

1530 m/s

Explanation:

Given that :

Speed = distance / time

Travel time take = 0.2 s

Distance covered = 306 metres

The speed of sound in the material :

Speed = distance / time = 306 m / 0.2

Speed = 1530 m/s

6 0
3 years ago
Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
4 years ago
How would you find kinetic energy?
Flura [38]

Answer:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

Explanation:

6 0
2 years ago
Read 2 more answers
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