Answer:
so the speed will increase by 1.44 times then the initial speed if the distance is increased to double
Explanation:
As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here
since we released it from rest so we have
so here we have
now if the distance is double then we have
now from above two equations we can say that
so the speed will increase by 1.44 times then the initial speed if the distance is increased to double
Answer:
The specific heat capacity is q_{L}=126.12kJ/kg
The efficiency of the temperature is n_{TH}=0.67
Explanation:
The p-v diagram illustration is in the attachment
T_{H} means high temperature
T_{L} means low temperature
The energy equation :
= R*
in(
/
)
The specific heat capacity:
=q_{h}*(T_{L}/T_{H})
q_{L}=378.36 * (400/1200)
q_{L}=378.36 * 0.333
q_{L}=126.12kJ/kg
The efficiency of the temperature will be:
=1 - (
/
)
n_{TH}=1-(400/1200)
n_{TH}=1-0.333
n_{TH}=0.67
Answer:
T = 60 s
Explanation:
There are 6 poles on the track which are equally spaced
so the angular separation between the poles is given as
so the angular speed of the train is given as
now we have time period of the train given as