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Alex17521 [72]
3 years ago
9

Very large accelerations can injure the body, especially if they last for a considerable length of time. One model used to gauge

the likelihood of injury is the severity index ( ???????? ), defined as ????????=????5/2???? . In the expression, ???? is the duration of the accleration, but ???? is not equal to the acceleration. Rather, ???? is a dimensionless constant that = the number of multiples of ???? that the acceleration is equal to.In one set of studies of rear-end collisions, a person's velocity increases by 13.7 km/h with an acceleration of 36.0 m/s2 . Let the +???? direction point in the direction the car is traveling. What is the severity index for the collision?
Physics
2 answers:
ryzh [129]3 years ago
4 0
Wait I’m confused as soon as you did the ????????
White raven [17]3 years ago
3 0

Answer:

SI=

How far d does the person travel during the collision if the car was initially moving forward at 4.50 km/h ?

d=

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Tracy's foot is pushing on her cars gas pedal, is it pushing or pulling back?
UkoKoshka [18]

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You are the design engineer in charge of testing the crashworthiness of new automobile models. Cars are tested by smashing them
BaLLatris [955]

Answer:

average force  is 138900 N

Explanation:

given data

speed = 50 km/h = 13.89 m/s

mass = 1500 kg

time = 0.15 s

to find out

average force

solution

we know initial velocity of car is positive

we will apply here equation to find force that is

Force x change in time that is equal to  mass x change in speed    ................1

so put here all value of mass, time and velocity in equation 1

Force x 0.15 =  1500 x ( -13.89)

force = 138900 N

so average force  is 138900 N

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3 years ago
In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

   The radius is  r =  59.8 \  cm  =  0.598 \ m

   The force is  F =  30.9 \ N

   The speed of the ball is  v = 16.0 \ m/s.

Generally the kinetic energy at the top of the circle is mathematically represented as

    K_t  =  \frac{1}{2} *  m  *  v^2

=> K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2  

=> K_t  =  31.36 \ J  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       W =  F *  d

Here  d is the length of  a semi - circular arc which is mathematically represented as

       d =  \pi * r

So

      W =  30.9 *  0.598

      W = 18.48 \ J

Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

=>   K_b  =  0.1225  *  v_b^2

From the law of energy conservation

     K_t +  W  =K_b

=>    31.36+  18.48 = 0.1225  *  v_b^2

=>    v_b = 20.17 \ m/s

3 0
4 years ago
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