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2 years ago

How many moles are in a solution that has a molarity of 3.0M and a volume of 1500 ml.

Chemistry

1 answer:

Bad White [126]2 years ago

3 0

Answer:

1.25 Moles

Explanation:

1.25 moles of solute

Explanation:

Molarity is defined as the number of moles of solute per liter of solution.

Molarity = moles of solute / liter of solution

We are given the molarity and volume, both of which have the correct units. All we have to do is rearrange the equation to find the number of moles. You can do this by multiplying both sides of the equation by the volume to cancel it out on the right hand side. Afterwards, you should end up having the volume multiplied by the molarity equaling the number of moles of solute like so:

Moles of solute = Molarity * Volume

2.5M HCl * 0.5 L = 1.25 moles of HCl

I hope this made sense.

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Okay so this is half math half chemistry...

AleksandrR [38]

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2 years ago

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3 years ago

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An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?

aleksley [76]

Answer:- Formula of the hydrate is $Fe_2(SO_4)_3.5H_2O$ and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

$81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})$

= $0.204molFe_2(SO_4)_3$

$18.4gH_2O(\frac{1mol}{18.02g})$

= $1.02molH_2O$

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

$Fe_2(SO_4)_3=\frac{0.204}{0.204}$ = 1

$H_2O=\frac{1.02}{0.204}$ = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is $Fe_2(SO_4)_3.5H_2O$ and the name of the hydrate is Iron(III)sulfate pentahydrate.

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2 years ago

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3 years ago

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Nadusha1986 [10]

Answer:

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