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Stella [2.4K]
3 years ago
15

The volume of gas is 200.0

Chemistry
1 answer:
Ber [7]3 years ago
7 0

Answer:

40 atm.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 200 mL

Initial pressure (P₁) = 2 atm

Final volume (V₂) = 10 mL

Temperature = constant

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

2 × 200 = P₂ × 10

400 = P₂ × 10

Divide both side by 10

P₂ = 400 / 10

P₂ = 40 atm

Thus, the final pressure of the gas is 40 atm.

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Ammonia gas decomposes to form nitrogen and hydrogen gases. NH3(g) → N2(g) 3H2(g) If the nitrogen gas is collected in a rigid 2
sveticcg [70]

Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas (\rm N_{2}) in the cylinder is 1.63 moles.

<h3>What is the ideal gas equation?</h3>

The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

\rm PV = nRT

Where,

Pressure (P) = 2000 kPa

Volume (V) = 2L

Temperature (T) = 295 K

Gas constant (R)=  0.08206

Substituting values  in the equation:

\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{2000 \times (\dfrac{1}{101.325}) \times 2}{0.08206 \times 295}\\\\&= 1.63\;\rm mol\end{aligned}

Therefore, 1.63 moles are produced.

Learn more about ideal gas equation here:

brainly.com/question/26720901

6 0
2 years ago
Hydrogen gas
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Answer:

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3 0
3 years ago
How many molecules of glucose are produced by each cycle of the light reaction?
disa [49]
Zero (0) molecules of glucose are produced.
4 0
3 years ago
1 point
Bumek [7]

Answer:

1 mole of C2H6.

Explanation:

The balanced equation for the reaction is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

We can determine the number of mole of C2H6 that reacted to produce 2 moles of CO2 as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 4 moles of CO2.

Therefore, Xmol of C2H6 will react to produce 2 moles of CO2 i.e

Xmol of CO2 = (2 x 2)/4

Xmol of CO2 = 1 mole.

Therefore, 1 mole of C2H6 is required to produce 2 moles of CO2.

6 0
3 years ago
What is the percent by mass of Fluorine in Nitrogen triflouride NF3?
Kipish [7]

Answer:

The answer to your question is 80.3%

Explanation:

Data

Percent by mass of F

molecules NF₃

Process

1.- Calculate the molar mass of nitrogen trifluoride

molar mass = (1 x 14) + (19 x 3)

                    = 14 + 57

                    = 71 g

2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.

                       71 g of NF₃ ------------------ 100%

                       57 g of F   ------------------- x

                            x = (57 x 100)/71

                            x = 5700 / 71

                            x = 80.3%

3.- Conclusion

Fluorine is 80.3% by mass of the molecule NF₃

           

3 0
3 years ago
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