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fiasKO [112]
3 years ago
5

How does quantum theory explain the emission spectra of atoms?

Physics
2 answers:
Lesechka [4]3 years ago
5 0

Answer:

B. A single, specific amount of energy is associated with each movement of an electron between energy levels.

Explanation:

As we know by the Bohr's theory that total energy of an electron in a given energy state is given by

E_n = -13.6 \frac{z^2}{n^2}

now here if we will find the change in energy of two states then it is given by

\Delta E = E_2 - E_1

\Delta E = 13.6 z^2(\frac{1}{n_1^2} - \frac{1}{n_2^2})

now when this specific amount of energy is absorbed by the electron then only it will change the state of energy.

so here correct answer will be

B. A single, specific amount of energy is associated with each movement of an electron between energy levels.

ankoles [38]3 years ago
4 0
The correct answer is B.

Let us think of the classical theory first. In the classical theory, light is a wave that gives energy. This energy gradually helps the electron jump to a higher energy level.
In quantum theory, this is wrong; an electron cannot absorb a small amout of energy because there is not close enough state to jump to with that energy; only very specific amounts of energy lead to a change in orbital levels/ absorbance of energy. Also, each pair of energy levels has a specific energy difference that is needed from an electron so that it can move.
Hence, B is correct; all other sentences describe classical models of light-electron interactions

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A small lead ball, attached to a 1.75-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled
soldier1979 [14.2K]

Answer:

h = 57.6 m

Explanation:

First, we find the linear speed of the ball while in circular motion:

v = rω

where,

v = linear speed of ball = ?

r = radius of circle = length of rope = 1.75 m

ω = angular speed = (3 rev/s)(2π rad/1 rev) = 18.84 rad/s

Therefore,

v = (1.75 m)(18.84 rad/s)

v = 32.98 m/s

Now, we apply the 3rd equation of motion on the ball, when it breaks:

2gh = Vf² - Vi²

where,

g = - 9.8 m/s² (negative sign due to upward motion)

h = height covered = ?

Vf = Final Velocity = 0 m/s (since, the ball finally stops at highest point for a moment)

Vi = Initial Velocity = 32.98 m/s

Therefore,

2(- 9.8 m/s²)h = (0 m/s)² - (32.98 m/s)²

h = ( - 1088.12 m²/s²)/( - 19.6 m/s²)

h = 55.5 m

since, the ball was initially at a height of 2.1 m from ground. So, the total height from ground, will now become:

h = 55.5 m + 2.1 m

<u>h = 57.6 m</u>

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You have to reduce 2.00 an5.00 I order to use the×that=0.800
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2 years ago
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