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kumpel [21]
3 years ago
5

The molecule

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answer:cellulose

Explanation:

I just did it.

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THIS ASSIGNMENT IS DUE BY 5! PLEASE HELP!!
kipiarov [429]

Answer:

its not inclusive fitness which is confusing but

Explanation:

ill give the answer when I finish the test

4 0
3 years ago
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What is the force of attraction between the particles in a salt crystal
Papessa [141]

Answer:

Electrostatic attraction between the ions

Step-by-step explanation:

A salt crystal consists of Na⁺ and Cl⁻ ions stacked together in a crystal.

The ions have opposite charges, so they are electrostatically attracted to each other.

Because the ions are so close together, the attractive forces are quite large.

4 0
4 years ago
A 1 L container originally holds 0.4 mol of N2, 0.1 mol of O2, and 0.08 mole of NO. If the volume of the container holding the e
julsineya [31]

Answer:

a)  N_2=0.8mol/L

b)  O_2=0.2mol/L

c)  NO=0.16mol/L

Explanation:

From the question we are told that:

Moles 0f Nitrogen N_2=0.4

Moles 0f Oxygen O_2=0.1

Volume Decrease V_2=0.5L

Generally, the equation for Concentration is mathematically given by

C=\frac{moles}{V}

For Nitrogen

N_2=\frac{0.4}{0.5}

N_2=0.8mol/L

For Oxygen

O_2=\frac{0.1}{0.5}

O_2=0.2mol/L

For Nitrogen

NO=\frac{0.08}{0.5}

NO=0.16mol/L

3 0
3 years ago
The label on a pressurized can of spray disinfectant warns against heating the can above 130 degree fahrenheit . What are the co
Leviafan [203]

Answer : The temperature in degree Celsius and Kelvin is, 54.44^oC\text{ and }327.59K respectively.

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

where,

^oF = temperature in Fahrenheit  

^oC = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Fahrenheit is, 130

Now we have to determine the temperature in degree Celsius.

^oC=(^oF-32)\times \frac{5}{9}

^oC=(130^oF-32)\times \frac{5}{9}

^oC=54.44

Now we have to determine the temperature in Kelvin.

K=273.15+^oC

K=273.15+(54.44^oC)

K=327.59

Therefore, the temperature in degree Celsius and Kelvin are, 54.44^oC\text{ and }327.59K

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3 years ago
I NEED HELP ASAP PLEASE
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I belive it is thermal energy...

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