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4 years ago

8

What is the change in potential energy of an energetic 65 kg hiker who makes it from the floor of death valley to the top of mt.

whitney?

1 answer:

Umnica [9.8K]4 years ago

7 0

Check the attached file for the answer.

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When a sound source is moving away from an observer, the observer will hear a lower pitch. This is due to

iren2701 [21]

Lower Pitch Due to the change to a lower frequency

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3 years ago

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How was the Periodic Table of Elements developed and how are the elements arranged on it?

victus00 [196]

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In 1869 Russian chemist Dimitri Mendeleev started the development of the periodic table, arranging chemical elements by atomic mass. He predicted the discovery of other elements, and left spaces open in his periodic table for them.

Explanation:

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3 years ago

A basketball has a mass of 609 g. Moving to the right and heading downward at an angle of 32° to the vertical, it hits the floor

andrezito [222]

Answer:1.549 kg-m/s

Explanation:

Given

mass of basketball =609 g

ball is moving downward right at an angle of $32 ^{\circ}$ with vertical

After hitting the floor it moves with a speed of 3 m/s

change in Momentum in x direction

$P_x=musin32\hat{i} -mvsin32\hat{i}$

where u=3m/s

v=3m/s

m=mass of ball

$P_x=0$

Change in momentum in Y-direction

$P_y=-mucos32\hat{j}-mvcos32\hat{j}=-2mvcos32$

$P_y=-1.549\hat{j} kg-m/s$

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3 years ago

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 10 m from the takeoff point. you may want t

Stells [14]

<u>Answer:</u>

Takeoff speed of Kangaroo = 12.91 m/s

<u>Explanation:</u>

The distance reached by Kangaroo = 10 meter

Angle at which it jumps = 18°

The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.

Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity

Time taken for the projectile to reach ground:

Time taken = Two times of the time taken for the projectile to reach maximum height

Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g

Time taken for the projectile to reach ground = 2 u sin θ/g

So Range of projectile = $ucos\theta*\frac{2usin\theta}{g} =\frac{u^2sin2\theta}{g}$

We have Range = 10 meter, θ = 18⁰

Substituting

$10=\frac{u^2sin(2*18)}{9.8}\\ \\ u^2= 166.73\\ \\ u=12.91 m/s$

Takeoff speed of Kangaroo = 12.91 m/s

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3 years ago

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What happen as waves travel and objects in their path move?

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Do you mean when objects move as a direct result of the passing wave? Waves have energy and constitute a force, just like wind. Therefore that force is able to move objects in its path.

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4 years ago