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Sever21 [200]
3 years ago
8

What is the change in potential energy of an energetic 65 kg hiker who makes it from the floor of death valley to the top of mt.

whitney?

Physics
1 answer:
Umnica [9.8K]3 years ago
7 0
Check the attached file for the answer.

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Two cellists, one seated directly behind the other in an orchestra, play the same 220-Hz note for the conductor who is directly
Llana [10]

Answer:

d= 1.56 m

Explanation:

In order to have a constructive interference, the path difference between the sources of the sound, must be equal to an even multiple of the semi-wavelength, as follows:

⇒ d = d₂ - d₁ = 2n*(λ/2)

The minimum possible value for this distance, is when n=1, as it can be seen here:

dmin = λ

In any wave, there exists a fixed relationship between the wave speed, the frequency and the wavelength:

v = λ*f

If v = vsound = 343 m/s, and f = 220 1/s, we can solve for λ:

λ =\frac{v}{f} =  \frac{343 m/s}{220(1/s)} = 1.56 m

⇒ dmin =λ = 1.56 m

3 0
3 years ago
When a 109 dB sound wave comes through an open window of area 0.485 m2, how much acoustic energy passes through the window in a
Ksju [112]

Answer:

57dB

Explanation:

7 0
3 years ago
What is the part of the earth that you walk on called?
olasank [31]
The part of the Earth that you walk on is called the CRUST.
6 0
3 years ago
How long with it take an object to accelerate from 6 m/s to 13 m/s at a rate of 1.4<br> m/s2. *
Blizzard [7]

Explanation:

hello,

a = ( v - u ) / t

where u is the initial velocity.

and v is the final velocity.

t represents time,

and a represents acceleration.

in this case,

a = 1.4 m/s²

u = 6 m/s

v = 13 m/s

hence,

1.4 = (13 - 6)/t

1.4t = 7

t = 7/1.4

t = 5 s

thank you!

7 0
2 years ago
Suppose you could suddenly increase the speed of every molecule in a gas by a factor of 2. Would the gas pressure increase by a
Elena L [17]

<h2>The pressure will become double </h2>

Explanation:

The gas pressure is directly proportional to the mean root square velocity of the constituent molecules of gas .

P ∝ \sqrt{\frac{C_1^2+C_2^2+C_3^2----C_n^2}{n} }      I

Here C₁ , C₂ ------------ Cₙ is the velocities of molecules .

By making these velocities double

The pressure P₀ ∝ 2\sqrt{\frac{C_1^2+C_2^2+C_3^2----C_n^2}{n} }          II

By dividing II by I

P₀ = 2 P

Thus pressure will become double than its previous value

5 0
3 years ago
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