Answer:
irreversible head loss is 38.51 ft
mechanical power 6.55 hp
Explanation:
Given data:
Pump Power 12 hp = 8948.39 watt = 6600 lbs ft/sec
Q = 1.5 ft^3/s
Pump actually delivers
Power that water gains
hence Power lost = 6600 - 2995.2 3604.8 lbs ft/sec = 6.55 hp
head loss
hl = 38.51 ft
Answer:
a) periodic (N = 1)
b) not periodic
c) not periodic
d) periodic (N = 8)
e) periodic (N = 16)
Explanation:
For function to be a periodic: f(n) = f(n+N)
It is periodic with fundamental period N = 1
N must be integer. So it is nor periodic
Since N is dependent to n. So it is not periodic.
So it is periodic with fundamental period N = 8.
So it is periodic with N = 16.
Answer: = 28800 Pa or 28.8 kPa
Explanation: To determine the pressure of a liquid in a rotating tank,it is used:
p = - γfluid . z + c
where:
is the liquid's density
w is the angular velocity
r is the radius
γfluid.z is the pressure variation due to centrifugal force.
For this question, the difference between a point on the circumference and a point on the axis will be:
=
- γfluid.
- (
- γfluid.
)
=
- γfluid(
-
)
Since there is no variation in the z-axis, z = 0 and that the density of oil is 0.9.10³kg/m³:
=
= 28800
The difference in pressure between two points, one on the circumference and the other on the axis is = 28800 Pa or 28.8 kPa