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il63 [147K]
3 years ago
5

Describe the preparation of2.ool of o. 108M Bacl2 fromBacl2.2HO (244.3 /mol)​

Chemistry
1 answer:
ololo11 [35]3 years ago
5 0

Answer:

We have to weigh 52.8 g of BaCl₂·2H₂O, add it to a 2.00 L flask and add water until reaching the final volume.

Explanation:

<em>Describe the preparation of 2.00 L of 0.108 M BaCl₂ from BaCl₂·2H₂O. (244.3 g/mol).</em>

Step 1: Calculate the moles of BaCl₂

We need to prepare 2.00 L of a solution that contains 0.108 moles of BaCl₂ per liter of solution.

2.00 L × 0.108 mol/L = 0.216 mol

Step 2: Calculate the moles of BaCl₂·2H₂O that contain 0.216 moles of BaCl₂

The molar ratio of BaCl₂·2H₂O to BaCl₂ is 1:1. The moles of BaCl₂·2H₂O required are 1/1 × 0.216 mol = 0.216 mol.

Step 3: Calculate the mass corresponding to 0.216 mol of BaCl₂·2H₂O

The molar mass of BaCl₂·2H₂O is 244.3 g/mol.

0.216 mol × 244.3 g/mol = 52.8 g

We have to weigh 52.8 g of BaCl₂·2H₂O, add it to a 2.00 L flask and add water until reaching the final volume.

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The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


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Aerosol cans have a label that warns the user not to use them above a certain temperature and not to dispose of them by incinera
Arturiano [62]

Answer:

1.90 atm

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

According to above equation, at constant Volume and number of moles, pressure is directly proportional to the temperature. So,

\frac {P_1}{T_1}=\frac {P_2}{T_2}

Given ,  

P₁ = 1.51 atm

P₂ = ?

T₁ = 23 °C

T₂ = 100 °C  ( boiling point of water )

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (23 + 273.15) K = 296.15 K  

T₂ = (100 + 273.15) K = 373.15 K  

Using above equation as:

\frac{1.51}{296.15}=\frac{P_2}{373.15}

P_2=\frac{1.51\cdot \:373.15}{296.15}\ atm

<u>New Pressure = 1.90 atm</u>

5 0
3 years ago
If 7.0 moles of HCl is added to enough iron that the HCl is completely used up, how many
Inessa05 [86]

Answer:

3.5 mol

Explanation:

Step 1: Given data

Moles of HCl: 7.0 mol

Step 2: Write the balanced equation

Fe(s) + 2 HCl(aq) ⇒ FeCl₂(aq) + H₂(g)

Step 3: Calculate the moles of H₂ gas produced from 7.0 moles of HCl

According to the balanced equation, the molar ratio of HCl to H₂ is 2:1.

7.0 mol HCl × 1 mol H₂/2 mol HCl = 3.5 mol H₂

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When heat is added to a substance describe how the molecules are affected brainly?
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When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of the particles determines the state of matter of the substance. The end result of increased molecular motion is that the object expands and takes up more space.
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4 years ago
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