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Maksim231197 [3]
3 years ago
7

What is the element 3O2 name​

Chemistry
1 answer:
bija089 [108]3 years ago
5 0

Answer:

Triplet oxygen

Explanation:

Based on my research it is called Triplet Oxygen, if this is wrong I'm sorry

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Chanice drives her scooter 7 kilometers north she stops for lunch and then drives 5 kilometers east what distance did she cover?
Serhud [2]
Her displacement is 2 i think

6 0
3 years ago
Read 2 more answers
The mass of an object is 32g and its density is 17g /mL. what is its volume
guajiro [1.7K]

Explanation:

here,

Mass (m)= 32 g =0.32 kg

Density(d)= 17 g/ml

volume (v)=?

we know that,

d=m/v

17=0.32/v

v= 0.32/17

v=0.018<u> </u>

3 0
3 years ago
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A compound is found to have a composition of 35.880% Cr, 21.076% P, and 43,545% O
stepan [7]

Explanation:

Cr=35.880/51=0.73≈0.7

P=21.076/31=0.67≈0.7

O=43.543/16=2.71

Divide each by 0.7 u get

Cr=1 ,P =1, O=4

Empirical formula is CrPO4

3 0
3 years ago
"Thermite" reactions have been used for welding metal parts such as railway rails and in metal refining. One such thermite react
frosja888 [35]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

3Mg(s)+Cr_2O_3(s)\rightarrow 3MgO(s)+2Cr(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(3\times \Delta S^o_{(MgO(s))})+(2\times \Delta S^o_{(Cr(s))})]-[(3\times \Delta S^o_{(Mg(s))})+(1\times \Delta S^o_{(Cr_2O_3(s))})]

We are given:

\Delta S^o_{(Mg(s))}=32.68J/K.mol\\\Delta S^o_{(Cr_2O_3(s))}=81.2J/K.mol\\\Delta S^o_{(MgO(s))}=26.94J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(3\times (26.94))+(2\times (23.77))]-[(3\times (32.68))+(1\times (81.2))]\\\\\Delta S^o_{rxn}=-50.88J/K=-0.0509kJ/K.mol

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

To calculate the standard Gibbs free energy of the reaction, we use the equation:

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy = ?

\Delta H^o = standard enthalpy change of the reaction = 665.1 kJ/mol

T = Temperature = 298.15 K

\Delta S^o = standard entropy change of the reaction = -0.0509 kJ/K.mol

Putting values in above equation, we get:

\Delta G^o=(665.1kJ/mol)-(298.15K\times (-0.0509kJ/K.mol))=680.27kJ/mol

As, the Gibbs free energy of the reaction is coming out to be positive, the reaction is non-spontaneous in nature.

Hence, the given reaction is non-spontaneous in nature.

4 0
4 years ago
What is the formula mass for carbon dioxide?
scZoUnD [109]
The molecular mass of the compound CO2 is calculate by simply taking the number of atoms of each element and multiplying it by the molar mass of the element on the periodic table.

C = 1 • 12.0 g/mol
O2 = 2 • 16.0 g/mol = 32.0 g/mol
CO2 = 12.0 + 32.0 = 44.0 g/mol.

The formula mass of CO2 is 44.0 g/mol.
3 0
3 years ago
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