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Paladinen [302]
3 years ago
12

Select the correct answer from each drop-down menu.

Physics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

Explanation:

the attraction is maximum between b and c. while the force between a and d is minimum

sweet-ann [11.9K]3 years ago
3 0

the attraction is maximum between b and c. while the force between a and d is minimum

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How do i do this???/
Gekata [30.6K]
Start at the big tree, and take the instructions one at a time: 1). Walk 15 west. 2). From there, turn around and walk 2 east. 3). From there, walk 7 more east. Where are you from the big tree now ? Aren't you 6 west of it ? I mean, let's see some common sense here !
5 0
3 years ago
Read 2 more answers
3. No simple machine is ideal in practice.<br>Why​
Kobotan [32]

Answer:

beacuase

Explanation:

4 0
3 years ago
An archer standing on a 15 degree slope shoots an arrow at an angle of 26 degrees above the horizontal. How far below its origin
aivan3 [116]

Answer:

The arrow will hit 112.07 m from the point of release.

Explanation:

The equation for the position of an object in a parabolic movement is as follows:

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

Where:

x0 = initial horizontal position

v0 = initial velocity

α = launching angle

y0 = initial vertical position

t = time

g = acceleration due to gravity

We know that at the final time the y-component of the vector "r" (see figure") is -1.88 m. The x-component of that vector will be the horizontal distance traveled by the arrow. Using the equation of the y-component of "r", we can obtain the final time and with that time we can calculate the value of the x-component (horizontal distance).

Then:

y = y0 + v0 · t · sin α + 1/2 · g · t²

Since the origin of the frame of reference is located at the point where the arrow is released, y0 = 0. Notice that the angle α = 26° + 15° = 41° ( see figure)

-1.88 m = 33 m/s · sin 41° · t - 1/2 · 9.8 m/s² · t²    (g is downward)

0 = -4.9 m/s² · t² + 33 m/s · sin 41° · t + 1.88 m

Solving the quadratic equation:

t = 4.5 s   ( the negative value is discarded)

Now, with this time we can calculate the horizontal distance:

x = x0 + v0 · t · cos α    (x0 = 0, the same as y0)

x = 33 m/s · 4.5 s · cos 41° = 112.07 m

6 0
3 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 9.0 s. At thi
sertanlavr [38]

Answer

given,

angular speed of the tub = 5 rev/s

time = 9 s

he tub slows to rest  =  15.0 s

the angular acceleration

\omega_f - \omega_i = \alpha t

\alpha = \dfrac{5-0}{9}

\alpha = 0.556 rev/s^2

angular displacement

\theta_1 = \omega_i \ t + \dfrac{1}{2}\alpha t^2

\theta_1 = \dfrac{1}{2}\times 0.556 \times 9^2

\theta_1 = 22.52 rev

\theta_1 = 23 rev

case 2

now,

\omega_i = 5 rev/s

\omega_f = 0 rev/s

time = 15 s

the angular acceleration

\omega_f - \omega_i = \alpha t

\alpha = \dfrac{0-5}{15}

v\alpha =-0.333 rev/s^2

angular displacement

\theta_2 = \omega_i \ t + \dfrac{1}{2}\alpha t^2

\theta_2 =5\times 15 -\dfrac{1}{2}\times 0.333 \times 15^2

\theta_2 = 37.875 rev

\theta_2 =38 rev

total revolution in 24 s

= 23 + 38

= 62 revolution

8 0
3 years ago
In a motion diagram, the size of the object must be less than the distance moved.
insens350 [35]
Is there  more to this question
4 0
3 years ago
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