I think it is with screens l, chemicals, and filters
I hope this helped
Rydberg Eqn is given as:
1/λ = R [1/n1^2 - 1/n2^2]
<span>Where λ is the wavelength of the light; 2626 nm = 2.626×10^-6 m </span>
<span>R is the Rydberg constant: R = 1.09737×10^7 m-1 </span>
<span>From Brackett series n1 = 4 </span>
<span>Hence 1/(2.626×10^-6 ) = 1.09737× 10^7 [1/4^2 – 1/n2^2] </span>
<span>Some rearranging and collecting up terms: </span>
<span>1 = (2.626×10^-6)×(1.09737× 10^7)[1/16 -1/n2^2] </span>
<span>1= 28.82[1/16 – 1/n2^2] </span>
<span>28.82/n^2 = 1.8011 – 1 = 0.8011 </span>
<span>n^2 = 28.82/0.8011 = 35.98 </span>
<span>n = √(35.98) = 6</span>
Answer:
a. True
Explanation:
Molecule -
- It refers to a group of two or more than two atoms , which can exists freely on it own , is referred to as a molecule .
- The molecule is a neutral group , where the atoms are bounded by chemical bonds .
- Molecule have a characteristic property of the substance.
Hence, the given statement about molecule , is true.
When answering the above question or problem, <span>first thing to realize is that the dissolution of the Na3PO4 can be written in a format that may be easier to see what is happening here. </span>
<span>Na3PO4 ----> 3 Na(+) + PO4(-3) </span>
<span>Now, you are starting out with a 0.35 M solution of Na3PO4, but when you dissolve the Na3PO4 into solution there are 3 Na(+) ions made for every Na3PO4 molecule that dissolves. Therefore to calculate the concentration of Na(+) ions in the final solution, take 3 times the inital concentration. 0.35 * 3 = 1.05 M in Na(+)</span>
