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patriot [66]
4 years ago
13

"You are asked to classify an exocrine gland found in the skin based solely on the chemical analysis of its product, which turns

out to be a hypotonic fluid consisting of about 99% water with a pH of 5. It contains NaCl, traces of urea and ammonia, and a peptide called dermcidin, but lacks fats and proteins. How would you classify this gland?"
Chemistry
2 answers:
guapka [62]4 years ago
6 0

Answer:

eccrine gland

Explanation:

The eccrine gland is a type of sweat gland and represents an excretory channel that takes unnecessary substances or sweat to the surface of the skin. These glands are found throughout the body and act from birth to the individual's motto.

These glands are characterized by the presence of hypotonic fluid composed of about 99% water with a pH of 5. It can also contain NaCl, traces of urea and ammonia, and a peptide called dermcidin, but it lacks fats and proteins.

Mice21 [21]4 years ago
5 0

Answer:

sweat glands

Explanation:

sweat glands are the only ones that can produce dermcidin, Nacl, urea and ammonia.  

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A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
3 years ago
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stira [4]
The answer is A, the contras  x Good luck!! :)

7 0
4 years ago
Resonance structures are not real. An individual resonance structure does not accurately represent the structure of a molecule o
tatiyna

Answer:

True

Explanation:

Resonance is a concept in chemistry that describes bonding in polyatomic molecules or ions whose structure cannot be efficiently described by a single Lewis structure. Individual resonance structures do not actually exist, that is, they are not real. None of the contributing resonance structures can be said to adequately represent the molecule or ion. However, the hybrid of all the possible resonance structures of the molecule or ion gives a holistic representation of the exact structure of the molecule or ion.

4 0
4 years ago
How much work is done by a person who lifts a weight 2 meters off of the ground by using a force of 55 Newtons?
EastWind [94]

Answer:

D. 110 Joules

Explanation:

Work = Force x Distance

The given force here is 55 Newtons, and the distance the object moved against the force is 2 meters.

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Hope this helped!

8 0
3 years ago
A sealed container has 1 mole of helium and 2 moles of nitrogen at 30DC when the total pressure of mixture is 0.60 atm what is t
bezimeni [28]

Answer:

The partial pressure of  nitrogen is  0.402 atm.

Explanation:

Given data:

Number of moles of helium = 1 mol

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Total pressure of mixture = 0.60 atm

Partial pressure of nitrogen = ?

Solution:

First of all we will calculate the mole fraction of nitrogen.

mole fraction of nitrogen = moles of nitrogen / total number of moles

mole fraction of nitrogen = 2 mol / 3 mol = 0.67

Partial pressure of nitrogen:

P₁ = [ n₁ /n(t)] × Pt

P₁ = 0.67 × 0.60 atm

P₁ = 0.402 atm

7 0
4 years ago
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