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Chemistry

1 answer:

Naily [24]2 years ago

5 0

Answer:

C. 9.70

Explanation:

Hello,

This problem is a simple dilution problem which utilizes the formula M1V1= M2V2 (where M is molarity, V is volume). I have attached a helpful image as well.

M1 V1 = M2 V2

(18) (x) = (0.35) (500)

x = 9.72mL which is close enough to option C.

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Answer : (C) Hafnium is the most likely identity of the given substance.

Solution : Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 $Cm^{3}$

First, find the Density of given substance.

Formula used :

$Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}$

Now,put all the values in this formula, we get

$Density=\frac{46.9 g}{3.5 Cm^{3} }$ = 13.4 g/ $Cm^{3}$

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Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

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