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swat32
3 years ago
9

PLZ Help asap!!!!

Chemistry
1 answer:
Naily [24]3 years ago
5 0

Answer:

C. 9.70

Explanation:

Hello,

This problem is a simple dilution problem which utilizes the formula M1V1= M2V2 (where M is molarity, V is volume). I have attached a helpful image as well.

M1 V1 = M2 V2

(18) (x) = (0.35) (500)

x = 9.72mL which is close enough to option C.

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Read 2 more answers
Determine the temperature change when 150. G block of gold is supplied with 1.00 • 10 ^3 J of heat
IceJOKER [234]

Answer:

∇T = 51.68°C

Explanation:

Mass = 150g

Heat Energy (Q) = 1.0*10³J

Change in temperature ∇T = ?

Q = mc∇T

Q = heat energy

M = mass

C = specific heat capacity of the gold = 0.129j/g°C

∇T = change in temperature

Q = Mc∇T

1.0*10³ = 150 * 0.129 * ∇T

1000 = 19.35∇T

Solve for ∇T

∇T = 1000 / 19.35

∇T = 51.679°C = 51.68°C

The change in temperature of gold was 51.68°C

8 0
3 years ago
What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog
anastassius [24]

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


 Explanation

Coefficient   is defined  to  as  a number  in front   of a chemical formula in a  balanced chemical equation.

   The  reaction   of   molybdenum (iv) oxide  with  gaseous  hydrogen  is  as below,


MoO2  + 2 H2→  Mo  +2 H2O

From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



3 0
3 years ago
Which one is ittt? help please:)
Alexus [3.1K]

Answer:

b

Explanation:

4 0
3 years ago
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