Answer:
lower is write answer is am write
Explanation:
number of mole s of H
2
= 0.25 moles
number of molecules = moles * Avogadro’s Number
number of molecules = 0.25×(6.022×10
23
)
number of molecules = 1.505×10
23
single molecule of hydrogen contains two H-atoms. So,
number of atoms = 2×(1.505×10
23
) = 3.01×10
23
Answer:
Explanation:
glucose-1-phosphate → glucose-6-phosphate, ΔGo = -7.28 kJ/mol
fructose-6-phosphate → glucose-6-phosphate, ΔGo = -1.67 kJ/mol
subtracting the equation
glucose-1-phosphate - fructose-6-phosphate = 0 , ΔGo = -7.28 - ( -1.67 ) kJ / mol
glucose-1-phosphate = fructose-6-phosphate ΔGo = - 5.61 kJ / mol
- ΔGo = RT lnK
5.61 x 10³ = 8.31 x 298 x lnK
lnK = 2.265
K = 9.63 .
Answer:
Mass = 28.59g
Explanation:
Q = 952J
Change in temperature = 37.0°C
Specific heat capacity = 0.90J/g°C
Mass = ?
Heat Energy (Q) = mc∇T
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇T = change in temperature of substance
Q = mc∇T
952 = m × 0.90 × 37
952 = 33.3m
Solve for m
M = 952 / 33.3
M = 28.59g
The mass of aluminium required to use a heat energy of 952J is 28.59g
Answer: The new pressure is 0.509 atm
Explanation:
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of gas = 1.20 atm
= final pressure of gas = ?
= initial volume of gas = 580 ml
= final volume of gas = 1.45 L = 1450 ml (1L=1000ml)
= initial temperature of gas = ![22^0C=(22+273)K=295K](https://tex.z-dn.net/?f=22%5E0C%3D%2822%2B273%29K%3D295K)
= final temperature of gas = ![40^0C=(40+273)K=313K](https://tex.z-dn.net/?f=40%5E0C%3D%2840%2B273%29K%3D313K)
Now put all the given values in the above equation, we get:
![\frac{1.20\times 580}{295}=\frac{P_2\times 1450}{313}](https://tex.z-dn.net/?f=%5Cfrac%7B1.20%5Ctimes%20580%7D%7B295%7D%3D%5Cfrac%7BP_2%5Ctimes%201450%7D%7B313%7D)
![P_2=0.509atm](https://tex.z-dn.net/?f=P_2%3D0.509atm)
The new pressure is 0.509 atm