The answer is C Becuz D is a compound and that is the only answer that says it
Answer:
Reducing sugars are absent
Explanation:
Benedict's solution is an substance used in testing sugars. It is mixture of sodium carbonate, sodium citrate and copper(II) sulfate pentahydrate. It can be used instead of Fehling's solution in testing for the presence of reducing sugars.
Reducing sugars contain the -CHO group. If there is no colour change after the addition of Benedict's solution, then we can conclude that reducing sugars are absent.
<span>C6H12O6 + O2 --> CO2 +H2O </span>
<span>In the balancede form we have: </span>
<span>C6H12O6 + 6O2 ---> 6CO2 + 6H2O </span>
<span>C -6 , H -12 and O - 18 </span>
<span>in both sides.</span>
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Answer: briitle would be easy to dislove
Explanation: