Ask question

Ask question

All categories

3 years ago

14

Electrons are ______. A. Constantly changing charges B. Positively charged and attracted to the nucleus C. Negatively charged an

d found outside the nucleus D. Neutral at all times

1 answer:

Anvisha [2.4K]3 years ago

8 0

Your answer is C, negative & outside

You might be interested in

Suppose that a certain biologically important reaction is quite slow at physiological temperature (37 oC) in the absence of a ca

Oksi-84 [34.3K]

Answer:

30 kJ

Explanation:

Arrhenius equation is given by:

$k=Aexp(-Ea/RT)\\$

Here, k is rate constant, A is Pre-exponential factor, Ea is activation energy and T is temperature.

taking natural log of both side

ln k = ln A - Ea/RT

In Arrhenius equation, A, R and T are constant.

Therefore,

$ln\frac{k_2}{k_1} =\frac{Ea_1-Ea_2}{RT}$

$Ea_1-Ea_2$ is the lowering in activation energy by enzyme,

R = 8.314 J/mol.K

T = 37°C + 273.15 = 310 K

$\frac{k_2}{k_1} =1\times 10^5$

$ln 1\times 10^5 =\frac{Ea_1-Ea_2}{RT}\\{Ea_1-Ea_2} = 11.512 \times 8.314 \times 310\\=29670\ J\\=30\ kJ$

4 0

3 years ago

What is the de Broglie wavelength (in meters) of a 45-g golf ball traveling at 72 m/s?

Cerrena [4.2K]

Answer: The de broglie wavelength is $2.037 \times 10^{-34} m$ .

Explanation:

Calculate $\lambda = \frac{h}{p}$ as follows.

$\lambda = \frac{h}{p}$

where,

h = plank's constant = $6.6 \times 10^{-34} m^{2} kg/s$

p = momentum = $mass \times velocity$

Putting the values in the formula as follows.

$\lambda = \frac{h}{mass \times velocity}$

= $\frac {6.6 \times 10^{-34} m^{2} kg/s}{0.045 kg \times 72 m/s}$

= $2.037 \times 10^{-34} m$

Thus, the de broglie wavelength is $2.037 \times 10^{-34} m$ .

6 0

3 years ago

Read 2 more answers

___Mg + ___Fe2O3 -> ___MgO + ___Fe

kipiarov [429]

3 Mg, 0 Fe2O3, 3MgO, 2 Fe

5 0

2 years ago

True or False: Electrons in each lower level are filled before electrons fill

ale4655 [162]

the answer is 1....true

5 0

3 years ago

What coefficient for O2 demonstrates the law of conservation of mass?

olga2289 [7]

Answer:

2

Explanation:

The coefficient for O is 2 and this is an example of a combustion reaction. With the help of the coefficient 2 infront of oxygen, this equation now demonstrates law of conservation of mass.

6 0

3 years ago