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Oksi-84 [34.3K]
3 years ago
5

Sinisimulan ko Kaya Ko Gagawin ko Nalaman ko Natututo Ako

Physics
1 answer:
ozzi3 years ago
7 0

Answer:

what!!!!!!

Explanation:

didn't got the point

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Please help me with this!!
Alja [10]

Answer:

C

Explanation:

Action and Reaction forces are equal in the opposite direction.

3 0
3 years ago
A pump of power 1500W is used for 5 mins the energy supplied by the pump is​
Anika [276]

Answer:

300W

Explanation:

from my years in middle school, i have learned the equation is energy =power*time is 300W

7 0
4 years ago
The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is
Ann [662]

40kg

Explanation:

Given parameters:

Kinetic energy  = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

          K.E = \frac{1}{2} mv²

  m is the mass of the body

  v is the velocity

 To find the mass, make it the subject of the expression:

         m = \frac{2 K.E}{v[tex]^{2}}[/tex]

          m =   \frac{2 x 500}{5[tex]^{2}}[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

4 0
4 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

We can use the following equation of motion to calculate how far the car has travel since braking to stop

s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
3 years ago
Mechanical efficiency is a comparison of a machines work output with the work input. True or False?
mr_godi [17]
The answer to this question is true
6 0
3 years ago
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